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Lana71 [14]
3 years ago
12

Can someone help me with this one?

Mathematics
2 answers:
Viktor [21]3 years ago
8 0
The slope of the line is - 3/2
Mice21 [21]3 years ago
7 0
1 1/2
Hope this helped!
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The expression 1/2bh gives the area of a triangle where b is the base of the triangle and h is the height of the triangle. What
iren [92.7K]

Hey there!

Let's plug these values into the formula.

1/2(7(4))

1/2(28)

14

Therefore, our area would be 14 sq cm.

I hope this helps!

8 0
3 years ago
Read 2 more answers
Why is it helpful to rewrite inequalities
mr_godi [17]

Answer:

  that puts the solution in the form ...

     variable is ...

Step-by-step explanation:

It isn't always.

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Often, we like to have a solution be in the form ...

  variable is ...

So, for an inequality, that puts the variable on the left:

  x > 3

  y < 27

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Personally, I like to see the answer in a form that has the variable and its values in the same relation as on a number line. This means, my preferred inequality symbols are < or ≤, since those have the smaller numbers on the left. I would write the first example above as ...

  3 < x

showing that the shaded portion of the number line (representing possible values of the variable) is to the right of the open circle at 3. For me, it is more mental effort to translate x > 3 to the same image.

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The forms we choose to use are all about making communication as easy as possible.

7 0
3 years ago
Subtract and simplify answer.
Schach [20]

(s^2+5st-9t^2)-(2s^2-2st+2t^2)=\\\\=s^2+5st-9t^2-2s^2+2st-2t^2=\\\\=s^2-2s^2-9t^2-2t^2+5st+2st=\boxed{-s^2-11t^2+7st}

7 0
3 years ago
Read 2 more answers
a) A standard deck consists of 52 cards. Four of the cards are aces. Twenty-six of the cards are red. A poker hand consists of 5
Rzqust [24]

Answer:

a)The number of aces in the poker hand is greater

b)It is about\sqrt{2} as accurate.

5 0
3 years ago
Solve the equations 1. 16x^2-1=0 2. 36z^2 96z 15=0
Allisa [31]
16x^2-1=0 2 

16x^2-1=0 2:x 

&#10;16x^2=1&#10; &#10;   |Add \ 1 \ to \ both \ sides|

x^2= \dfrac{1}{16}   |Divide \ both \ sides \ by \ 16|<span>
</span>
x^2= \sqrt{\dfrac{ \sqrt{1}}{ \sqrt{16}}}  |Take \ the \ square \ root \ of \ both \ sides|

x= \dfrac{1}{4}


5 0
3 years ago
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