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2 years ago

15. Express 2/5 as a percentage

Mathematics

2 answers:

blsea [12.9K]2 years ago

7 0

Answer:

$40\%$

Step-by-step explanation:

$\frac{2}{5} \times 100 = 40\%$

Vanyuwa [196]2 years ago

5 0

Divide 2 by 5 to get a decimal, then multiply the decimal by 100 to get a percent.

2/5 = 0.4

0.4x100 = 40

2/5 = 40%

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Step-by-step explanation:

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2 years ago

Suppose a production facility purchases a particular component part in large lots from a supplier. The production manager wants

musickatia [10]

Answer:

We need a sample size of at least 1161.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The margin of error for the interval is:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

For this problem, we have that:

$\pi = 0.22$

90% confidence level

So $\alpha = 0.1$ , z is the value of Z that has a pvalue of $1 - \frac{0.1}{2} = 0.95$ , so $Z = 1.645$ .

How large a sample should she take?

We need a sample size of at least n.

n is found when $M = 0.02$

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.02 = 1.645\sqrt{\frac{0.22*0.78}{n}}$

$0.02\sqrt{n} = 1.645\sqrt{0.22*0.78}$

$\sqrt{n} = \frac{1.645\sqrt{0.22*0.78}}{0.02}$

$(\sqrt{n})^{2} = (\frac{1.645\sqrt{0.22*0.78}}{0.02})^{2}$

$n = 1160.88$

Rounding up

We need a sample size of at least 1161.

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3 years ago

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yes-9.45

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yes-9.86

Step-by-step explanation:

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2 years ago

What is 400 divided by 2/3

notsponge [240]

Answer:

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Step-by-step explanation:

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2 years ago

15. Express 2/5 as a percentage​

15. Express 2/5 as a percentage