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3 years ago

The table below shows the average temperature, in degrees Celsius, in Jacobs city over a period of five months

Mathematics

1 answer:

katen-ka-za [31]3 years ago

3 0

Linearly, because the table shows that temperature increased by the same amount each month (2.2). If it were exponentially, the temperature would increase by the same percentage each month.

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Solve the equation 4\pi =w-6\pi

maksim [4K]

Answer:

4/pi=w-6/pi

4 = w-6

Pi pi

Cross mutiply

Pi(w-6)=4(pi)

Wpi - 6pi =4pi

Collect like terms

Wpi=4pi + 6pi

Wpi =10pi

Divide both sides by pi

Wpi = 10pi

Pi pi

W = 10

5 0

3 years ago

A yogurt costs 45 pence how many yogurts can be bought for 5 pounds

Oliga [24]

11.
for a total of 4.95
you would have 5 pence remaining.

6 0

3 years ago

Read 2 more answers

In a 5 km race, Anna swims 450 m, then runs 800 m. She then cycles the rest of the race. How many kilometres does she cycle?

Umnica [9.8K]

5km = 5000 meters
450m+800m= 1250m
5000m-1250m= 3,750m
3 3/4 km

6 0

4 years ago

Mathematically verify the outlier(s) in the data set using the 1.5 rule.

statuscvo [17]

Given:

The data values are:

7, 8, 11, 13, 14, 14, 14, 15, 16, 16, 18, 19

To find:

The outliers of the given data set.

Solution:

We have,

7, 8, 11, 13, 14, 14, 14, 15, 16, 16, 18, 19

Divide the data set in two equal parts.

(7, 8, 11, 13, 14, 14), (14, 15, 16, 16, 18, 19)

Divide each parenthesis in two equal parts.

(7, 8, 11), (13, 14, 14), (14, 15, 16), (16, 18, 19)

Now,

$Q_1=\dfrac{11+13}{2}$

$Q_1=\dfrac{24}{2}$

$Q_1=12$

And

$Q_3=\dfrac{16+16}{2}$

$Q_3=\dfrac{32}{2}$

$Q_3=16$

The interquartile range is:

$IQR=Q_3-Q_1$

$IQR=16-12$

$IQR=4$

The data values lies outside the interval $[Q_1-1.5IQR,Q_3+1.5IQR]$ are known as outliers.

$[Q_1-1.5IQR,Q_3+1.5IQR]=[12-1.5(4),16+1.5(4)]$

$[Q_1-1.5IQR,Q_3+1.5IQR]=[12-6,16+6]$

$[Q_1-1.5IQR,Q_3+1.5IQR]=[6,22]$

All the data values lie in the interval [6,22]. So, there are no outliers.

Hence, the correct option is 4.

3 0

3 years ago

e Ann, Claire, and Josh collect stickers. One week, Ann collects 7 more stickers than Josh. Josh collects twice as many stickers

lisabon 2012 [21]

Answer: Ann = 67 Josh = 60 Claire = 30

Step-by-step explanation: You get the equation 5x+7 = 157. You get the equation because for example, Claire = x then josh = 2x and Ann = 2x + 7. You do all the math and boom! You get the answer :)

4 0

4 years ago