Answer:
Equations are
20c + 10m = 495..............(1)
8c + 1m = 178.5.................(2)
Now , equation (2) * 10 = 80c + 10m = 1785...........(3)
So, Eq. (3) - Eq(1) =
80c + 10m - 20c - 10m = 1785 - 495
60c = 1290
c= 21.5
********************************************************
Now place the value of c in Eq (2)
So , m =6.5
Mark my answer as brainlist answer
Step-by-step explanation:
Answer:
Error:
not 
Solution:x=0 and 3
Step-by-step explanation:
We have to find the error and correct answer
Given:![2ln x=ln(3x)-[ln9-2ln(3)]](https://tex.z-dn.net/?f=2ln%20x%3Dln%283x%29-%5Bln9-2ln%283%29%5D)
![lnx^2=ln(3x)-[ln9-ln3^2]](https://tex.z-dn.net/?f=lnx%5E2%3Dln%283x%29-%5Bln9-ln3%5E2%5D)
Using the formula
![lnx^2=ln(3x)-[ln9-ln9]](https://tex.z-dn.net/?f=lnx%5E2%3Dln%283x%29-%5Bln9-ln9%5D)
Therefore, x=0 and x=3
But last step in the given solution
It is wrong this property is used when
then
Hence, the student wrote 
instead of 
and solution is given by
x=0 and x=3
The answer is 3 (x+b) (x-2)
Yw! :)
Answer:
Step-by-step explanation:
h(x)=12/x
h(a)= 12/a ( a is a variable number just replace x with a)
