-30x-12y+36x-12y
Combine the x' s first
6x-12y-12y
Combine the y's
6x-24y is your answer
Answer:
a^2+6a+9
Step-by-step explanation:
Given:
First term of an arithmetic sequence is 2.
Sum of first 15 terms = 292.5
To find:
The common difference.
Solution:
We have,
First term: 
Sum of first 15 terms: 
The formula of sum of first n terms of an AP is
![S_n=\dfrac{n}{2}[2a+(n-1)d]](https://tex.z-dn.net/?f=S_n%3D%5Cdfrac%7Bn%7D%7B2%7D%5B2a%2B%28n-1%29d%5D)
Where, a is first term and d is common difference.
Putting , n=15 and a=2 in the above formula, we get
![292.5=\dfrac{15}{2}[2(2)+(15-1)d]](https://tex.z-dn.net/?f=292.5%3D%5Cdfrac%7B15%7D%7B2%7D%5B2%282%29%2B%2815-1%29d%5D)
![292.5=\dfrac{15}{2}[4+14d]](https://tex.z-dn.net/?f=292.5%3D%5Cdfrac%7B15%7D%7B2%7D%5B4%2B14d%5D)
![292.5=15[2+7d]](https://tex.z-dn.net/?f=292.5%3D15%5B2%2B7d%5D)
Divide both sides by 15.
Dividing both sides by 7, we get
Therefore, the common difference is 2.5.
Answers:
1. There are rivets on the belts.
2. Extra information given in the problem:
a. He has 9 buckles.
b. He has 22 rivets left over.
Solution:
1. Total rivets on the belts=(12 rivets/belt)(4 belts)+(15 rivets/belt)(2 belts)
Total rivets on the belts=48 rivets+30 rivets
Total rivets on the belts=78 rivets
2. The extra information given in the problem is the information that we didn't use to solve it. In this case:
a. He has 9 buckles.
b. He has 22 rivets left over.
Answer:
96^2in
Step-by-step explanation:
4x4=16
16x6=96
