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Mars2501 [29]
3 years ago
5

Which of the following graphs shows a pair of lines that represent the equations with a solution (−2, 5)?

Mathematics
1 answer:
const2013 [10]3 years ago
3 0

Answer:

The first one (top)

Step-by-step explanation:

The coordinate plane works with coordinates being x, y, and so if x is -2, then it would be to the left of 0. 5 is above 0, and you see the 2 lines intersecting at that point.

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2 and 5. What is the LCM?
Masja [62]
Well, first of all, LCM means Lowest Common Multiple. So you have to write out the factors of each of the numbers. So that will be;
2= 2, 4, 6, 8, 10, 12, 14, 16, 18, 20
5=5, 10, 15, 20
  So now, you have to pick out the numbers that are common to both numbers. So;
10, 20
  10 and 20 are the only common numbers. So you have to look for the lowest common number. And that is 10. So the LCM is 10.. Hope i helped. Have a nice day. 
5 0
3 years ago
Which expression is a difference of squares with a factor of 2x5?
Sedbober [7]

Answer:

{( \sqrt{3.5} })^{2}  -  {( \sqrt{1.5} )}^{2}

Step-by-step explanation:

The difference of two squares identity is

{x}^{2}   -  {y}^{2}  = (x  - y)(x + y)

When we let

\sqrt{3.5}

and

\sqrt{1.5}

, we get:

{( \sqrt{3.5} )}^{2}  -  {( \sqrt{1.5}) }^{2}  = (3.5 - 1.5)(3.5 + 1.5)

This will simplify to give us the required factors

{( \sqrt{3.5} )}^{2}  -  {( \sqrt{1.5}) }^{2}  =2 \times 5

7 0
3 years ago
Dependent probability
mina [271]
4/13 chance to get green and 6/13 to get red
8 0
3 years ago
If yu were to randomly survey 500 people each from two largest us cities would this be a random study why or why not HELP NEEDED
Valentin [98]

Answer:

If you're timed then I would say,

Yes this is a random study because the problem specifically states that the survey samples were randomly selected from populations.

I think that is the answer! However, if you have time I would wait for another person to answer as well because I'm terrible at statistics :(

6 0
3 years ago
SOMEONE HELP ME PLS, I'M stuck on this one since yesterday!
AfilCa [17]
\bf \begin{cases}
F = \{(0, 1), (\stackrel{x}{2}, \stackrel{y}{4}), (4, 6), (6, 8)\} &  F(\stackrel{x}{2})=\stackrel{y}{4}
\\\\\\
G = \{(\stackrel{x}{2}, \stackrel{y}{5}), (4, 7), (5, 8), (6, 9), (7, 5)\} \qquad & G(\stackrel{x}{2})=\stackrel{y}{5}
\end{cases} 
\\\\\\
(F\cdot G)(2)\implies F(2)\cdot G(2)\implies 4\cdot 5\implies 20
7 0
3 years ago
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