Do you have a picture of the proble that will help me understand it more so I can help you
Answer:
5/6 and 5/6
Step-by-step explanation:
<u>City A:</u>
step 1: find the mean (average)
(4 + 3.5 + 5 + 5.5 + 4 + 2) / 6 = 4
step 2 and 3: find the difference between each data value and the mean AND take the absolute value of each difference
|4 - 4| = 0
|3.5 - 4| = |-0.5| = 0.5
|5 - 4| = 1
|5.5 - 4| = 1.5
|4 - 4| = 0
|2 - 4| = |-2| = 2
step 4: find the mean (average) of these differences
(0 + 0.5 + 1 + 1.5 + 0 + 2) / 6 = 5/6
<u>City B:</u>
step 1: find the mean (average)
(5 + 6 + 3.5 + 5.5 + 4 + 6) / 6 = 5
step 2 and 3: find the difference between each data value and the mean AND take the absolute value of each difference
|5 - 5| = 0
|6 - 5| = 1
|3.5 - 5| = |-1.5| = 1.5
|5.5 - 5| = 0.5
|4 - 5| = |-1| = 1
|6 - 5| = 1
step 4: find the mean (average) of these differences
(0 + 1 + 1.5 + 0.5 + 1 + 1) / 6 = 5/6
Hope this helps!
It will hit the floor when h=0
-16t^2+14.8t+3.9=0
using the quadratic formula...
t=(-14.8±√468.64)/-32, since t>0
t ≈ 1.139 seconds
Answer:
The small balloon bouquet uses 7 balloons and the large one uses
18 balloons.
Step-by-step explanation:
Let's say that small balloon bouquets are S and large balloon bouquets are L. For the graduation party the employee assembled 6 small bouquets and 6 large bouquets, the total number of balloon used is 150. To put the sentence into an equation will be:
6S + 6L= 150
S+L= 25 ----> 1st equation
For Father's Day, the employee uses 6 small bouquet and 1 large bouquet, the total number of balloons used is 60. The equation will be:
6S + 1L= 60
1L= 60- 6S ----> 2nd equation
We can solve the number of small balloon bouquet by substitute the 2nd equation into 1st. The calculation will be:
S+L = 25
S+ (60-6S)= 25
-5S= 25-60
-5S= -35
S= -35/-5
S=7
Then we can find L by substitute S value to 1st or 2nd equation.
S+L=25
7+L=25
L=18
Mode, because mode is the number that shows up most often.
