Not a function because it does not pass the horizontal line test. It has 2 solutions
Answer:
I would start the graph at (0,36) and go down 12, right 1 until you reach the end of the graph
Step-by-step explanation:
Hope it helps
Answer:
C. 5x² - 4
General Formulas and Concepts:
<u>Algebra I</u>
- Composite Functions
- Combining Like Terms
Step-by-step explanation:
<u>Step 1: Define</u>
f(x) = 4x² + 1
g(x) = x² - 5
(f + g)(x) is f(x) + g(x)
<u>Step 2: Find (f + g)(x)</u>
- Substitute: (f + g)(x) = 4x² + 1 + x² - 5
- Combine like terms: (f + g)(x) = 5x² - 4
<h2>
The area of a triangle is =54 square units</h2><h2>
The perpendicular distance from B to AC is = 
</h2>
Step-by-step explanation:
Given a triangle ABC with vertices A(2,1),B(12,2) and C(12,8)

The area of a triangle is= ![\frac{1}{2} [x_1(y_2-y_3) +x_2 (y_3- y_1)+x_3(y_1-y_2)]](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7D%20%5Bx_1%28y_2-y_3%29%20%2Bx_2%20%28y_3-%20y_1%29%2Bx_3%28y_1-y_2%29%5D)
=![|\frac{1}{2} [2(2-8+12(8-1)+12(1-2)]|](https://tex.z-dn.net/?f=%7C%5Cfrac%7B1%7D%7B2%7D%20%5B2%282-8%2B12%288-1%29%2B12%281-2%29%5D%7C)
=
= 54 square units
The length of AC = 
= 
=
units
Let the perpendicular distance from B to AC be = x
According To Problem

⇔
units
Therefore the perpendicular distance from B to AC is = 
Multiply the fraction by 100%.
