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Naily [24]
3 years ago
8

Considee the linear equation 5x+2y=-20. Determine the x-intercept and the y-intercept and use them to graph the line and find th

e slope of the line.
Mathematics
1 answer:
Vilka [71]3 years ago
5 0

Answer:

x-intercept is (-4,0); y-intercept is (0, -10).

Step-by-step explanation:

To find the x-intercept, set y = 0 and solve for x:

5x + 2(0) = -20.  Then 5x = -20, or x = -4.  The x-intercept is (-4,0).

To find the y-intercept, set x = 0 and solve for y:

5(0) + 2y = -20.  Thus, y = -10.  The y-intercept is (0, -10).

Now we have two points on the line, both intercepts.

As we go from (-4,0) to (0, -10), x increases by 4 and y decreases by 10.

Thus, the slope of this line is m = rise / run = -10/4 = -5/2.

The easiest way to graph this line is to plot the two intercepts (-4,0) and (0, - 10) and draw a line through these two points.

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Answer:

x = 2

Step-by-step explanation:

3(2x + 6) - 4x = 2(5x - 2) + 6 \\   6x + 18 - 4x = 10x - 4 + 6 \\ 2x + 18 = 10x + 2 \\ 18 - 2 = 10x - 2x \\ 16 = 8x \\ x =  \frac{16}{8}  \\  \huge \:  \red { \boxed{x = 2}}

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Using the slope formula, find the slope of the line through the points (0,0) and (4,8).
Gala2k [10]

Answer:

m = 2

Step-by-step explanation:

<u>Using mental math to find the slope of the line:</u>

If you think about the formula, then you set up the points in your head, you will notice that the first point is on top of the second point. And that way makes it easy to simplify. All you would need to do is subtract down in your head: For example:

(0, 0)

(4, 8)

As you can see, the first point is on top of the other, and that way you can just subtract from bottom to top. If you do it that way, it is set up (Remember, you would do this all in your head)

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3 years ago
What are the roots of the quadratic equation x2+2x=-5
stiks02 [169]

Answer:

x = -1 +/-2i

Step-by-step explanation:

Write the equation in standard form to find the roots, also known as the solutions, zeros, or x-intercepts, of the quadratic.

x² + 2x + 5 = 0

Use the quadratic formula by substituting a= 1, b = 2 and c = 5.

x = \frac{-2 +/- \sqrt{(-2)^2 - 4(1)(5)} }{2(1)} = \frac{-2 +/-\sqrt{4 -20 } }{2} = \frac{-2 +/-\sqrt{-16 } }{2} = \frac{-2 +/-4i }{2} = -1 +/-2i

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