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Naily [24]
3 years ago
8

Considee the linear equation 5x+2y=-20. Determine the x-intercept and the y-intercept and use them to graph the line and find th

e slope of the line.
Mathematics
1 answer:
Vilka [71]3 years ago
5 0

Answer:

x-intercept is (-4,0); y-intercept is (0, -10).

Step-by-step explanation:

To find the x-intercept, set y = 0 and solve for x:

5x + 2(0) = -20.  Then 5x = -20, or x = -4.  The x-intercept is (-4,0).

To find the y-intercept, set x = 0 and solve for y:

5(0) + 2y = -20.  Thus, y = -10.  The y-intercept is (0, -10).

Now we have two points on the line, both intercepts.

As we go from (-4,0) to (0, -10), x increases by 4 and y decreases by 10.

Thus, the slope of this line is m = rise / run = -10/4 = -5/2.

The easiest way to graph this line is to plot the two intercepts (-4,0) and (0, - 10) and draw a line through these two points.

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Jacob Lee is a frequent traveler between Los Angeles and San Diego. For the past month, he wrote down the flight times in minute
valkas [14]

Solution :

We know that

$H_0: \mu_1 = \mu_2=\mu_3$

$H_1 :$ At least one mean is different form the others (claim)

We need to find the critical values.

We know k = 3 , N = 35, α = 0.05

d.f.N = k - 1

       = 3 - 1 = 2

d.f.D = N - k

        = 35 - 3 = 32

SO the critical value is 3.295

The mean and the variance of each sample :

Goust                      Jet red                 Cloudtran

$\overline X_1 =50.5$           $\overline X_2 =50.07143$        $\overline X_3 =55.71429$

$s_1^2=19.96154$      $s_2^2=14.68681$         $s_3^2=36.57143$

The grand mean or the overall mean is(GM) :

$\overline X_{GM}=\frac{\sum \overline X}{N}$

         $=\frac{51+51+...+49+49}{35}$

        = 52.1714

The variance between the groups

$s_B^2=\frac{\sum n_i\left( \overline X_i - \overline X_{GM}\right)^2}{k-1}$

     $=\frac{\left[14(50.5-52.1714)^2+14(52.07143-52.1714)^2+7(55.71426-52.1714)^2\right]}{3-1}$

   $=\frac{127.1143}{2}$

   = 63.55714

The Variance within the groups

$s_W^2=\frac{\sum(n_i-1)s_i^2}{\sum(n_i-1)}$

    $=\frac{(14-1)19.96154+(14-1)14.68681+(7-1)36.57143}{(14-1)+(14-1)+(7-1)}$

   $=\frac{669.8571}{32}$

  = 20.93304

The F-test  statistics value is :

$F=\frac{s_B^2}{s_W^2}$

  $=\frac{63.55714}{20.93304}$

  = 3.036212

Now since the 3.036 < 3.295, we do not reject the null hypothesis.

So there is no sufficient evidence to support the claim that there is a difference among the means.

The ANOVA table is :

Source       Sum of squares    d.f    Mean square    F

Between    127.1143                 2      63.55714          3.036212

Within        669.8571             32      20.93304

Total           796.9714            34

3 0
3 years ago
. can someone help pls
disa [49]

Answer:

The answer is 3,906.25

Step-by-step explanation:

All you have to do is divide 15,625 by 4! :)

6 0
3 years ago
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