Answer:
m∠Q ≈ 53°
Step-by-step explanation:
To find the measure of ∠Q, the law of cosines will need to be used. Lowercase letters represent the side lengths, while upper case letters represent angles.
In this situation, 'A' will be ∠Q. Therefore:
17² = 18² + 20² -2(18)(20)cosQ
Simplify:
289 = 324 + 400 -2(360)cosQ
Continue simplifying down:
-435 = -720cosQ
Divide both sides by '-720':
0.604 = cosQ
![cos^{-1}Q = 0.604](https://tex.z-dn.net/?f=cos%5E%7B-1%7DQ%20%3D%200.604)
m∠Q ≈ 52.83 or 53° rounded to the nearest whole degree.
Answer:
4/5
Step-by-step explanation:
Answer:
Option A:
y = 3*(x - 5)^2 - 4
Step-by-step explanation:
For a quadratic equation:
y = a*x^2 + b*x + c
with the vertex (h, k), we can rewrite the function as:
such that:
h = -b/2*a
y = a*(x - h)^2 + k
Here we have the function:
y = 3*x^2 - 30*x + 71
the x-value of the vertex will be:
h = -(-30)/(2*3) = 30/6 = 5
And k is given by:
k = y(5) = 3*(5)^2 - 30*5 + 71 = -4
Then the vertex is:
(5, - 4)
And we can rewrite the equation in the vertex form as:
y = 3*(x - 5)^2 + (-4)
y = 3*(x - 5)^2 - 4
Then the correct option is A.
For both Carnivals to have the same cost, 10 tickets will have to be purchased.
Carnival M :
Entrance fee = $5.00
Cost per ticket = $0.50
Carnival P :
Entrance fee = $7.00
Cost per ticket = $0.30
Let the Number of ticket = n
Cost of n Carnival M tickets :
5 + 0.50n - - - (1)
Cost of n Carnival P tickets :
7 + 0.30n - - - (2)
Value of n in other to have the same price :
(1) = (2)
5 + 0.50n = 7 + 0.30n
Collect like terms
0.50n - 0.30n = 7 - 5
0.20n = 2
Divide both sides by 0.20
n = 2 / 0.20
n = 10
Therefore, 10 tickets has to be purchased for both Carnivals to have the same cost.
Learn more : brainly.com/question/18796573
The answer to your problem is x= 43