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sammy [17]
3 years ago
9

Divide 5346 divided by 29​

Mathematics
2 answers:
netineya [11]3 years ago
6 0

Answer:

594

Step-by-step explanation:

Snowcat [4.5K]3 years ago
3 0

Answer:

184.3448276

Step-by-step explanation:

5346/29

184.3448276

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yes your answer is 45 degree

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wren and jenni are reading the same book. wren is on page 14 and reads 2 pages every night. jenni is on page 6 and reads 3 pages
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If Jenni get one page closer to Wren every night and Wren has read 8 more pages then is will take Jenni 8 more nights to catch up to Wren. They will be on page 30 in their book.
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The length of the hypotenuse of a right triangle is 16 inches. If the length of one leg is 5 inches, what is the approximate len
Musya8 [376]

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15.2 inches

Step-by-step explanation:

a^2 + b ^2= c^2

5^2 + b ^2=16^2

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7 0
2 years ago
(3 − 4i)(5 + 2i)<br><br> A. 15 − 8i<br> B. 23 − 14i<br> C. 15 − 8i2<br> D. 15 − 14i − 8i2
choli [55]

Answer:

B.23-14i

Step-by-step explanation:

(3x5)+(3x2i)-(4ix5)-(4ix2i)

15+6i-20i-8(-1)

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8 0
3 years ago
The diameter of a particle of contamination (in micrometers) is modeled with the probability density function f(x)= 2/x^3 for x
natulia [17]

Answer:

a) 0.96

b) 0.016

c) 0.018

d) 0.982

e) x = 2

Step-by-step explanation:

We are given with the Probability density function f(x)= 2/x^3 where x > 1.

<em>Firstly we will calculate the general probability that of P(a < X < b) </em>

       P(a < X < b) =  \int_{a}^{b} \frac{2}{x^{3}} dx = 2\int_{a}^{b} x^{-3} dx

                            = 2[ \frac{x^{-3+1} }{-3+1}]^{b}_a   dx    { Because \int_{a}^{b} x^{n} dx = [ \frac{x^{n+1} }{n+1}]^{b}_a }

                            = 2[ \frac{x^{-2} }{-2}]^{b}_a = \frac{2}{-2} [ x^{-2} ]^{b}_a

                            = -1 [ b^{-2} - a^{-2}  ] = \frac{1}{a^{2} } - \frac{1}{b^{2} }

a) Now P(X < 5) = P(1 < X < 5)  {because x > 1 }

     Comparing with general probability we get,

     P(1 < X < 5) = \frac{1}{1^{2} } - \frac{1}{5^{2} } = 1 - \frac{1}{25} = 0.96 .

b) P(X > 8) = P(8 < X < ∞) = 1/8^{2} - 1/∞ = 1/64 - 0 = 0.016

c) P(6 < X < 10) = \frac{1}{6^{2} } - \frac{1}{10^{2} } = \frac{1}{36} - \frac{1}{100 } = 0.018 .

d) P(x < 6 or X > 10) = P(1 < X < 6) + P(10 < X < ∞)

                                = (\frac{1}{1^{2} } - \frac{1}{6^{2} }) + (1/10^{2} - 1/∞) = 1 - 1/36 + 1/100 + 0 = 0.982

e) We have to find x such that P(X < x) = 0.75 ;

               ⇒  P(1 < X < x) = 0.75

               ⇒  \frac{1}{1^{2} } - \frac{1}{x^{2} } = 0.75

               ⇒  \frac{1} {x^{2} } = 1 - 0.75 = 0.25

               ⇒  x^{2} = \frac{1}{0.25}   ⇒ x^{2} = 4 ⇒ x = 2  

Therefore, value of x such that P(X < x) = 0.75 is 2.

8 0
2 years ago
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