Answer:
3156
Step-by-step explanation:
- <em>Used formula:</em>
- <em>(1² + 2² + 3² + ... + n²) =1/6*n(n + 1)(2n + 1)</em>
--------
- 10²+12²+14²+......+26² =
- (2*5)²+(2*6)² + (2*7)² + ... + (2*13)² =
- 4*(5²+6²+7²+...+13²) =
- 4*(1²+2²+...+13² - (1²+2²+3²+4²)) =
- 4*(1/6*13(13+1)(2*13+1) - (1+4+9+16)) =
- 4*(1/6*13*14*27- 30) =
- 4*(819 - 30) =
- 4*789 =
- 3156
We can simplify 15/3 to 5.
N/6 = 5. Then multiply both sides of the equation by 6, giving us N = 30.
(3^2)3=27
27/3^x=3
3(3^x)=27
3^x=9
x=2
There are two parts of an equation (including this one), the coefficient, and the variable.
The coefficient is a known number, written as a digit, whereas the variable is an unknown number, written as a letter to signify an unknown number.
So, the coefficient in the first term (or part of the equation) is -2. The coefficient in the second term is 9, and the variable in this equation is x.
The completion is certainly not unique. Multiplying any of the new vectors by a nonzero constant will not affect the span or the linear independence<span>, but will change the </span>basis<span>. </span>To prove<span> that you can </span>extend<span> any </span>linearly independent set<span> S to a </span>basis<span>, you proceed by an iterative argument. If S spans you are done. hope this helps :)</span>
