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3 years ago

Help will mark brainliest for correct answer!!choices: 5/88/7(not -8/7)

Mathematics

2 answers:

r-ruslan [8.4K]3 years ago

8 0

The correct anwer is C I think... I hope That helps :)

||-//

Westkost [7]3 years ago

4 0

Answer:

$A : \frac{5}{8}$

Step-by-step explanation:

Axis Interception points of $\frac{5}{8}x - \frac{8}{7} :$ X intercepts: $(\frac{64}{35},0)$ , Y intercepts: $(0, -\frac{8}{7})$

Inverse of $\frac{5}{8}x-\frac{8}{7}:$ $\frac{56x+64}{35}$

Slope of $\frac{5}{8}x -\frac{8}{7}: m = \frac{5}{8}$

Hope I helped, if so may I get Brainliest and a thanks?

Thank you, have a good one! =)

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Rewrite 3 x 6/8 as the product of a unit fraction and a whole number

Elanso [62]

3/1×6/8=3/1×3/4=9/4=2 1/4

5 0

3 years ago

4 to the 8th power divided by 4 to the 5th power

Natasha2012 [34]

Alright, 4 to the 8th power is 4x4x4x4x4x4x4x4 which ends up as 65,536.

4 to the 5th power is the same thing but with 5 4's and that is 1,024.

All you need to do now is 65,536/1,024 = 64.

Solved! :D

6 0

3 years ago

Prove or disprove (from i=0 to n) sum([2i]^4) <= (4n)^4. If true use induction, else give the smallest value of n that it doe

ddd [48]

Answer:

The statement is true for every n between 0 and 77 and it is false for $n\geq 78$

Step-by-step explanation:

First, observe that, for n=0 and n=1 the statement is true:

For n=0: $\sum^{n}_{i=0} (2i)^4=0 \leq 0=(4n)^4$

For n=1: $\sum^{n}_{i=0} (2i)^4=16 \leq 256=(4n)^4$

From this point we will assume that $n\geq 2$

As we can see, $\sum^{n}_{i=0} (2i)^4=\sum^{n}_{i=0} 16i^4=16\sum^{n}_{i=0} i^4$ and $(4n)^4=256n^4$ . Then,

$\sum^{n}_{i=0} (2i)^4 \leq(4n)^4 \iff \sum^{n}_{i=0} i^4 \leq 16n^4$

Now, we will use the formula for the sum of the first 4th powers:

$\sum^{n}_{i=0} i^4=\frac{n^5}{5} +\frac{n^4}{2} +\frac{n^3}{3}-\frac{n}{30}=\frac{6n^5+15n^4+10n^3-n}{30}$

Therefore:

$\sum^{n}_{i=0} i^4 \leq 16n^4 \iff \frac{6n^5+15n^4+10n^3-n}{30} \leq 16n^4 \\\\ \iff 6n^5+10n^3-n \leq 465n^4 \iff 465n^4-6n^5-10n^3+n\geq 0$

and, because $n \geq 0$ ,

$465n^4-6n^5-10n^3+n\geq 0 \iff n(465n^3-6n^4-10n^2+1)\geq 0 \\\iff 465n^3-6n^4-10n^2+1\geq 0 \iff 465n^3-6n^4-10n^2\geq -1\\\iff n^2(465n-6n^2-10)\geq -1$

Observe that, because $n \geq 2$ and is an integer,

$n^2(465n-6n^2-10)\geq -1 \iff 465n-6n^2-10 \geq 0 \iff n(465-6n) \geq 10\\\iff 465-6n \geq 0 \iff n \leq \frac{465}{6}=\frac{155}{2}=77.5$

In concusion, the statement is true if and only if n is a non negative integer such that $n\leq 77$

So, 78 is the smallest value of n that does not satisfy the inequality.

Note: If you compute $(4n)^4- \sum^{n}_{i=0} (2i)^4$ for 77 and 78 you will obtain:

$(4n)^4- \sum^{n}_{i=0} (2i)^4=53810064$

$(4n)^4- \sum^{n}_{i=0} (2i)^4=-61754992$

7 0

3 years ago

What effect does doubling the radius of a cylinder have on the volume of the cylinder?

BabaBlast [244]

Doubling the radius of the cylinder will quadruple the volume.

3 0

3 years ago

Best explained/correct answer gets brainliest.

Nuetrik [128]

3, 15, 75, 375, and here's why:
Basically, it's asking you to take 3, and multiply it by five each time to get a pattern.

1: 3
2: 3*5 = 15
3: 15*5 = 75
4: 75*5 = 375

Add these together:
3 + 15 + 75 + 375 = 468

Your answer is "A)", 468.

5 0

3 years ago

Help will mark brainliest for correct answer!!choices: 5/88/7(not -8/7) ​

Help will mark brainliest for correct answer!!choices: 5/88/7(not -8/7)