I can’t tell if you want fraction or decimal so ima say 4/9
The formula for the volume of a triangular pyramid is:
V=1/3AH (where A=area of the base and H=height)
The formula for the volume of a triangular prism is:
V=AH (where A=area of the base and H=Height)
Since the base and the height are the same in this problem for both the prism and the pyramid, solving for the volume of the prism is simple.
Looking at the formulas, you'll see that the volume of the pyramid (assuming that both the height and the area of the base are the same) is 1/3 the volume of the prism.
V(pyramid)=1/3V(prism)
Now lets input the volume of the pyramid
26cm³=1/3 V(prism)
Divide both sides by 1/3
78cm³=V(prism)
Answer=78cm³
Answer: ![\pm0.1706](https://tex.z-dn.net/?f=%5Cpm0.1706)
Step-by-step explanation:
Given : Sample size : n= 33
Critical value for significance level of
: ![z_{\alpha/2}= 1.96](https://tex.z-dn.net/?f=z_%7B%5Calpha%2F2%7D%3D%201.96)
Sample mean : ![\overline{x}=2.5](https://tex.z-dn.net/?f=%5Coverline%7Bx%7D%3D2.5)
Standard deviation : ![\sigma= 0.5](https://tex.z-dn.net/?f=%5Csigma%3D%200.5)
We assume that this is a normal distribution.
Margin of error : ![E=\pm z_{\alpha/2}\dfrac{\sigma}{\sqrt{n}}](https://tex.z-dn.net/?f=E%3D%5Cpm%20z_%7B%5Calpha%2F2%7D%5Cdfrac%7B%5Csigma%7D%7B%5Csqrt%7Bn%7D%7D)
i.e. ![E=\pm (1.96)\dfrac{0.5}{\sqrt{33}}=\pm0.170596102837\approx\pm0.1706](https://tex.z-dn.net/?f=E%3D%5Cpm%20%281.96%29%5Cdfrac%7B0.5%7D%7B%5Csqrt%7B33%7D%7D%3D%5Cpm0.170596102837%5Capprox%5Cpm0.1706)
Hence, the margin of error is ![\pm0.1706](https://tex.z-dn.net/?f=%5Cpm0.1706)
Answer:
According with the graph:
1.) The equation of the regresion line is: y=5,720.10391 x + 957.225810
2.) The values of the correlation coefficient is 0.86
Step-by-step explanation:
In the graph is shown:
1.) Line of Best Fit
y=5720.10391 x + 957.225810
2.) Correlation
.86
Answer:
a number less then 6 is the anser so the 1st one