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seraphim [82]
3 years ago
9

Create a factorable polynomial with a GCF of 2y. Rewrite that polynomial in two other equivalent forms. Explain how each form wa

s created.
I already made my polynomial, 4y^1 + 6y^3
I just don't understand how to get two equivalent forms(please explain if you can)
Mathematics
1 answer:
Varvara68 [4.7K]3 years ago
6 0
4y^1 + 6y^3...so factor out the GCF for another form

2y(2 + 3y^2) <== here is one form

another form would be to multiply ur equation by a multiple of ur GCF 2, such as 4

4(4y^1 + 6y^3) = 16y^1 + 24y^3 <== another form
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Answer:

B. (2 + 5).

Step-by-step explanation:

18 + 45 = 63

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So 63 is a multiple of 7.

The answer is (2 + 5)  (=7).

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3 years ago
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Firlakuza [10]

Answer: x=−2

Step-by-step explanation:

Let's solve your equation step-by-step.

4(8−x)−32=98−5(3x+24)

Step 1: Simplify both sides of the equation.

4(8−x)−32=98−5(3x+24)

(4)(8)+(4)(−x)+−32=98+(−5)(3x)+(−5)(24)(Distribute)

32+−4x+−32=98+−15x+−120

(−4x)+(32+−32)=(−15x)+(98+−120)(Combine Like Terms)

−4x=−15x+−22

−4x=−15x−22

Step 2: Add 15x to both sides.

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Step 3: Divide both sides by 11.

11x /11 = −22 /11

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8 0
3 years ago
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Answer:

A

Step-by-step explanation:

expanding the bracket, we would have

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