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miskamm [114]
3 years ago
12

The sum of 18 +45 is a multiple of which sum?

Mathematics
1 answer:
forsale [732]3 years ago
6 0

Answer:

B. (2 + 5).

Step-by-step explanation:

18 + 45 = 63

The prime factors of 63 = 3*3*7

So 63 is a multiple of 7.

The answer is (2 + 5)  (=7).

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That would mean every word in the english language includes every letter of the alphabet.

A word with a 1/2 chance of a vowel is “Boat”
5 0
3 years ago
Please anwser fast and give an explanation step by step thank you
Ludmilka [50]

What is the question?

7 0
3 years ago
About 57 people rent skates at the skating rink each day. It cost $4.25 to rent skates. About how much does the Rink make in ska
seraphim [82]

Answer:1695.75

Step-by-step explanation:

We know that there are 7 days in a week. Since 57 people rent skates each day, we know that 57*7=399 skates are rented each week. Since one skate cost 4.25, we know that 399*4.25 is the cost, which is 1695.75. (If you are not allowed to use a calculator, you can do 400*4.25-4.25, to make it easier to compute)

4 0
3 years ago
A rectangular box is to have a square base and a volume of 12 ft3. If the material for the base costs $0.17/ft2, the material fo
katen-ka-za [31]

Answer:

(a)Length =2 feet

(b)Width =2 feet

(c)Height=3 feet

Step-by-step explanation:

Let the dimensions of the box be x, y and z

The rectangular box has a square base.

Therefore, Volume of the boxV=x^2z

Volume of the box=12 ft^3\\

Therefore, x^2z=12\\z=\frac{12}{x^2}

The material for the base costs \$0.17/ft^2, the material for the sides costs \$0.10/ft^2, and the material for the top costs \$0.13/ft^2.

Area of the base =x^2

Cost of the Base =\$0.17x^2

Area of the sides =4xz

Cost of the sides==\$0.10(4xz)

Area of the Top =x^2

Cost of the Base =\$0.13x^2

Total Cost, C(x,z) =0.17x^2+0.13x^2+0.10(4xz)

Substituting z=\frac{12}{x^2}

C(x) =0.17x^2+0.13x^2+0.10(4x)(\frac{12}{x^2})\\C(x)=0.3x^2+\frac{4.8}{x} \\C(x)=\dfrac{0.3x^3+4.8}{x}

To minimize C(x), we solve for the derivative and obtain its critical point

C'(x)=\dfrac{0.6x^3-4.8}{x^2}\\Setting \:C'(x)=0\\0.6x^3-4.8=0\\0.6x^3=4.8\\x^3=4.8\div 0.6\\x^3=8\\x=\sqrt[3]{8}=2

Recall: z=\frac{12}{x^2}=\frac{12}{2^2}=3\\

Therefore, the dimensions that minimizes the cost of the box are:

(a)Length =2 feet

(b)Width =2 feet

(c)Height=3 feet

7 0
3 years ago
A road crew took 3 days to pave a road. On the first day they paved 2/5 of the road, and on the second day they 1/3 of the road.
bazaltina [42]

Answer:5625 yards

Step-by-step explanation:

2/5=6/15

1/3=5/15

6/15+5/15=11/15

(15/15)-(11/15)=4/15

1500/4=375

375×15=5625

3 0
3 years ago
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