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Bas_tet [7]
3 years ago
15

If the general solution of a differential equation is ​y(t)equals=Upper C e Superscript negative 4 t Baseline plus 7Ce−4t+7​, wh

at is the solution that satisfies the initial condition ​y(0)equals=1010​?
Mathematics
2 answers:
Maru [420]3 years ago
8 0

Answer:

y(t) = 3e^{-4t}+7

Step-by-step explanation:

y(t) = Ce^{-4t}+7

At <em>y</em>(0) = 10, when <em>t</em> = 0, <em>y</em> = 10.

y(0) = 10 = Ce^{-4\times0}+7

10 = C+7

C = 3

Hence, the solution is

y(t) = 3e^{-4t}+7

Anuta_ua [19.1K]3 years ago
5 0

Answer:

a

Step-by-step explanation:

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