Question

If the general solution of a differential equation is ​y(t)equals=Upper C e Superscript negative 4 t Baseline plus 7Ce−4t+7​, what is the solution that satisfies the initial condition ​y(0)equals=1010​?

Answer 1

Answer:

$y(t) = 3e^{-4t}+7$

Step-by-step explanation:

$y(t) = Ce^{-4t}+7$

At y(0) = 10, when t = 0, y = 10.

$y(0) = 10 = Ce^{-4\times0}+7$

$10 = C+7$

$C = 3$

Hence, the solution is

$y(t) = 3e^{-4t}+7$

Answer 2

Answer:

a

Step-by-step explanation: