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____ [38]
3 years ago
12

The inequality of 8z+3-2z<51 is

Mathematics
1 answer:
masya89 [10]3 years ago
8 0
8z - 2z < 48
6z < 48
z < 8
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Adult tickets to an amusement park cost x dollars. Children's tickets cost y dollars. The Henson family bought 3 adult and 1 chi
Alex787 [66]

Henson's cost: 3x+y=203

Garcia's cost: 2x+3y=189

Step-by-step explanation:

Given,

Cost of each adult ticket = x dollars

Cost of 3 adult ticket = 3x

Cost of 2 adult ticket = 2x

Cost of each child ticket = y dollar

Cost of 3 child ticket = 3x

Henson's cost;

3 adult tickets + 1 child ticket = $203

3x+y=203

Garcia's cost;

2 adult tickets + 3 child tickets = $189

2x+3y=189

Henson's cost: 3x+y=203

Garcia's cost: 2x+3y=189

Keywords: linear equation, addition

Learn more about addition at:

  • brainly.com/question/10552347
  • brainly.com/question/10570041

#LearnwithBrainly

7 0
3 years ago
The net of a square pyramid and its dimensions are shown in the diagram. What is the total surface area of the pyramid in square
aniked [119]

Answer: the general formula for the total surface area of a regular pyramid isbT. S. A. =12pl+B where p represents the perimeter of the base

7 0
3 years ago
I need urgent help with this one
Serhud [2]

let the unknown answer be equal to f

.-2.1 - f = -3/2

-f = -3/2 + 2.1

-f = 0.6

f = -0.6

5 0
3 years ago
Read 2 more answers
I need help FAST!!!Make sure you can explain the problem
Pepsi [2]

Answer:

AB is not a tangent to the circle

Step-by-step explanation:

The angle between a tangent and the radius at the point of contact = 90°

Using Pythagoras' identity to determine if the triangle is right at A

If the square of the longest side is equal to the sum of the squares on the other 2 sides then A is right.

longest side = 15 , then 15² = 225

8² + 9² = 64 + 81 = 145 ≠ 225

Then AB is not a tangent to the circle

6 0
3 years ago
A box has three cards numbered 1, 2, and 3
Igoryamba

Answer:

{1A, 1B, 1C, 2A, 2B, 2C, 3A, 3B, 3C}

{1C, 2C, 3C}

Step-by-step explanation:

First is all possibilities.  Let's do it one step at a time.  The first step is the number, what are all the numbers that can be chosen?  1 2 and 3.  then, when you pick1, what are all the letters that can be chosen?  A B and C.  Do this for 2 and 3 and you get all possibilities.

{1A, 1B, 1C, 2A, 2B, 2C, 3A, 3B, 3C}

When you have steps like this you can multiply the number of results to get the total number of possibilities as well.  Step one has 3 results, step 2 has 3 results, that means there are 3*3 total, which is 9.  Do be careful it matches this  kind of setup, where the step 2 is the same for all step 1s.  So if instead if you got 1 for step 1 you picked from a bag with 3 things, then for 2 you picked from a different bag with a different number, that multiplication trick wouldn't work.

Now just pick throught he sample space to find all with C.  There are three, {1C, 2C, 3C}

7 0
3 years ago
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