Answer:
the answer is 2.9 x 10^0 and 3.2 x 10^-2
Step-by-step explanation:
10^0 is equal to 1 so 2.9 x 10^0 is really 2.9 times 1 which is less than 3
if i could get brainliest answer that would be great!
10^-2 is a exponential that makes a number go down so 3.2 going down is less than 3
Let p(x) be a polynomial, and suppose that a is any real
number. Prove that
lim x→a p(x) = p(a) .
Solution. Notice that
2(−1)4 − 3(−1)3 − 4(−1)2 − (−1) − 1 = 1 .
So x − (−1) must divide 2x^4 − 3x^3 − 4x^2 − x − 2. Do polynomial
long division to get 2x^4 − 3x^3 − 4x^2 – x – 2 / (x − (−1)) = 2x^3 − 5x^2 + x –
2.
Let ε > 0. Set δ = min{ ε/40 , 1}. Let x be a real number
such that 0 < |x−(−1)| < δ. Then |x + 1| < ε/40 . Also, |x + 1| <
1, so −2 < x < 0. In particular |x| < 2. So
|2x^3 − 5x^2 + x − 2| ≤ |2x^3 | + | − 5x^2 | + |x| + | − 2|
= 2|x|^3 + 5|x|^2 + |x| + 2
< 2(2)^3 + 5(2)^2 + (2) + 2
= 40
Thus, |2x^4 − 3x^3 − 4x^2 − x − 2| = |x + 1| · |2x^3 − 5x^2
+ x − 2| < ε/40 · 40 = ε.
Slope =2/3
70,80) (10,40)
(80-40)/(70-10) = 40/60
4/6
2/3
If you want to see if they are equivalent just substitute any number such as 2, so 2.5(2) = 5 and 2 + 5 = 7, so they are not equivalent (THIS IS TRUE UNLESS YOU DIDNT PUT THE X VALUE IN THE QUESTION)
We are aware that the numbers 4, 9, 25 and 49 are among those between 1 and 100 that have precisely three elements.
Given,
What number has three components?
In fact, the squares of primes are the only positive integers with precisely three factors. For instance, 1, 3, and 9 are the factors of 9, and 1, 7, and 49 are the factors of 49.
If a given number, such as x2, is perfect square, and its square root is prime, it must have precisely three different factors.
Here,
We are aware that the numbers 4, 9, 25 and 49 are among those between 1 and 100 that have precisely three elements.
1, 2, and 4 are the four factors. 1, 3, and 9 are the factors of 9.
Learn more about factors here;
brainly.com/question/103907
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