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IrinaVladis [17]
3 years ago
14

Solve the equation g^2-12g=-36​

Mathematics
2 answers:
Blababa [14]3 years ago
8 0

Let us begin by writing the given equation:

g² - 12g = - 36

Bringing all the terms to LHS for getting a quadratic equation,

g² - 12g + 36 = 0

Splitting the middle term,

g² - 6g - 6g + 36 = 0

Taking out common factors,

g ( g - 6 ) - 6 ( g - 6 ) = 0

Taking out common factors,

( g - 6 ) ( g - 6 ) = 0

( g - 6 )² = 0

( g - 6 ) = √0

g - 6 = 0

g = 6

Hence, after solving we get, g = 6

Tresset [83]3 years ago
6 0

\bold{Answer}

\boxed{\bold{G \ = \ 6}}

\bold{Explanation}

  • \bold{Solve: \ g^2-12g=-36}

\bold{---------------------}

  • \bold{Add \ 36 \ To \ Both \ Sides}

\bold{g^2-12g+36=-36+36}

  • \bold{Simplify}

\bold{g^2-12g+36=0}

  • \bold{Solve \ With \ Quadratic \ Formula}
  • \bold{a=1,\:b=-12,\:c=36:\quad g_{1,\:2}=\frac{-\left(-12\right)\pm \sqrt{\left(-12\right)^2-4\cdot \:1\cdot \:36}}{2\cdot \:1}}

\bold{\left(-12\right)^2-4\cdot \:1\cdot \:36 \ = \ 0}

\bold{g_{1,\:2}=\frac{-\left(-12\right)\pm \sqrt{0}}{2\cdot \:1}}

\bold{g=\frac{-\left(-12\right)}{2\cdot \:1}}

  • \bold{Simplify \ \frac{-\left(-12\right)}{2\cdot \:1} \ = \ 6}

\bold{g=6}

\boxed{\bold{Eclipsed}}

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