Question

Solve the equation g^2-12g=-36​

Answer 1

Let us begin by writing the given equation:

g² - 12g = - 36

Bringing all the terms to LHS for getting a quadratic equation,

g² - 12g + 36 = 0

Splitting the middle term,

g² - 6g - 6g + 36 = 0

Taking out common factors,

g ( g - 6 ) - 6 ( g - 6 ) = 0

Taking out common factors,

( g - 6 ) ( g - 6 ) = 0

( g - 6 )² = 0

( g - 6 ) = √0

g - 6 = 0

g = 6

Hence, after solving we get, g = 6

Answer 2

$\bold{Answer}$

$\boxed{\bold{G \ = \ 6}}$

$\bold{Explanation}$

• $\bold{Solve: \ g^2-12g=-36}$

$\bold{---------------------}$

• $\bold{Add \ 36 \ To \ Both \ Sides}$

$\bold{g^2-12g+36=-36+36}$

• $\bold{Simplify}$

$\bold{g^2-12g+36=0}$

• $\bold{Solve \ With \ Quadratic \ Formula}$
• $\bold{a=1,\:b=-12,\:c=36:\quad g_{1,\:2}=\frac{-\left(-12\right)\pm \sqrt{\left(-12\right)^2-4\cdot \:1\cdot \:36}}{2\cdot \:1}}$

$\bold{\left(-12\right)^2-4\cdot \:1\cdot \:36 \ = \ 0}$

$\bold{g_{1,\:2}=\frac{-\left(-12\right)\pm \sqrt{0}}{2\cdot \:1}}$

$\bold{g=\frac{-\left(-12\right)}{2\cdot \:1}}$

• $\bold{Simplify \ \frac{-\left(-12\right)}{2\cdot \:1} \ = \ 6}$

$\bold{g=6}$

$\boxed{\bold{Eclipsed}}$