First we need to look at the greatest and least points on each axis.
For x - the greatest is 2 and the least is -2 (that is the value of x for the points marked in the top left and right quadrants of the xy axis.
(Note that the points on the number line have a value for x of 1 & -1, but you need to look at highest value of points in all quadrants.)
For y - the greatest would be 3 and the least 0. Looking up and down the Y axis, you can see these intersections for the points given.
Now you need to find the D & R that is suitable for these values. We can only consider the first and last option because it correctly shows that the values for x & 7 must be between 2 & -2 and 0 and 3, The first one is incorrect because they have the D & R reversed. It is x that must be between 2 & -2 and y that must be between 0 & 3.
I hope you found this helpful.
Answer:
https://preview.redd.it/t4p9fgd30ag61.gif?format=mp4&s=56295791fda9b2006756326ff4863b84a5c30271
Step-by-step explanation:
Answer:
It means to the power.
Example*
2^2 = 2 to the power of 2 = 4
Answer:
1/10 per sec
Step-by-step explanation:
When he's walked x feet in the eastward direction, the angle Θ that the search light makes has tangent
tanΘ = x/18
Taking the derivative with respect to time
sec²Θ dΘ/dt = 1/18 dx/dt.
He's walking at a rate of 18 ft/sec, so dx/dt = 18.
After 3seconds,
Speed = distance/time
18ft/sec =distance/3secs
x = 18 ft/sec (3 sec)
= 54ft. At this moment
tanΘ = 54/18
= 3
sec²Θ = 1 + tan²Θ
1 + 3² = 1+9
= 10
So at this moment
10 dΘ/dt = (1/18ft) 18 ft/sec = 1
10dΘ/dt = 1
dΘ/dt = 1/10 per sec
The correct answer is linear
