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lapo4ka [179]
3 years ago
15

The perimeter of a rectangle is 182 ft. The width is two more feet than the length . Find the length and width.

Mathematics
1 answer:
Kamila [148]3 years ago
5 0

Let's call the width w and the length l based on this, we can make two equations based on the first and second sentences in the problem.

w = l + 2

2l + 2w = 182


If we substitute l + 2 for w into the second equation, we can make the following:

2l + 2(l + 2) = 182

  • Substitute

2l + 2l + 4 = 182

  • Use the Distributive Property

4l + 4 = 182

  • Combine like terms

4l = 178

  • Subtract 4 from both sides

l = \dfrac{178}{4} = \dfrac{89}{2}

  • Divide both sides by 4 and simplify

Now, let's find w:

w = l + 2 = \dfrac{89}{2} + 2 = \dfrac{93}{2}


The length of the rectangle is \boxed{\dfrac{89}{2} \,\textrm{ft}} and the width of the rectangle is \boxed{\dfrac{93}{2} \,\textrm{ft}}.

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