Answer : B, D
Step - by - step explanation :
6/16 Divided by 2/2 --> 3/8 ( so it's not 2/8 )
6/16 Multiplied by 2/2 --> 12/32 ( so it's not 12/18 )
30/80 --> 3.75 6/16 --> 3.75
The value placed in the box that makes the system of equation with infinitely many solution is 12.
<h3>How to solve an infinitely many solution equation?</h3>
An infinite solution has both sides equal. For example, 6x + 2y - 8 = 12x +4y - 16. If we simplify the equation we will notice both sides are equal. This means the equation has an infinitely many solution.
Hence,
y = -2x + 4
Therefore,
6x + 3y = 12
divide the equation(ii) by 3
2x + y = 4
y = -2x + 4
Therefore, both equation are equal if the the box is filled with 12. This means for the value placed in the box that makes the system of equation with infinitely many solution is 12.
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Answer:
see below (I hope this helps!)
Step-by-step explanation:
The x seems to represent the number of months that Leslie has joined the gym for. When x = 0 (basically when she hasn't started using her membership), she pays 55(0) + 50 = $50 so we know that the 50 represents the one-time fee. The only thing missing is the monthly fee and since we haven't defined what the 55 means, we can conclude that the 55 represents the monthly fee. This makes sense because 55x is simply 55 times x, and since x is the number of months, 55 times that would be how much Leslie pays per month, otherwise known as the monthly fee.
Answer:
look at the picture i have sent
Answer:
<h3><u>Cylinder</u></h3>
![\textsf{Volume of a cylinder}=\sf \pi r^2 h \quad\textsf{(where r is the radius and h is the height)}](https://tex.z-dn.net/?f=%5Ctextsf%7BVolume%20of%20a%20cylinder%7D%3D%5Csf%20%5Cpi%20r%5E2%20h%20%5Cquad%5Ctextsf%7B%28where%20r%20is%20the%20radius%20and%20h%20is%20the%20height%29%7D)
Given:
![\begin{aligned}\implies \sf V &= \sf \pi (6)^2(18)\\& = \sf 648 \pi \: cm^3\end{aligned}](https://tex.z-dn.net/?f=%5Cbegin%7Baligned%7D%5Cimplies%20%5Csf%20V%20%26%3D%20%5Csf%20%5Cpi%20%286%29%5E2%2818%29%5C%5C%26%20%3D%20%5Csf%20648%20%5Cpi%20%5C%3A%20cm%5E3%5Cend%7Baligned%7D)
<h3><u>Cube</u></h3>
![\textsf{Volume of a cube}=\sf x^3\quad\textsf{(where x is the side length)}](https://tex.z-dn.net/?f=%5Ctextsf%7BVolume%20of%20a%20cube%7D%3D%5Csf%20x%5E3%5Cquad%5Ctextsf%7B%28where%20x%20is%20the%20side%20length%29%7D)
Given:
![\begin{aligned}\implies \sf V &= 8^3\\& = \sf 512 \: cm^3\end{aligned}](https://tex.z-dn.net/?f=%5Cbegin%7Baligned%7D%5Cimplies%20%5Csf%20V%20%26%3D%208%5E3%5C%5C%26%20%3D%20%5Csf%20512%20%5C%3A%20cm%5E3%5Cend%7Baligned%7D)
<h3><u>Volume available to be filled with water</u></h3>
Volume of cylinder - volume of cube
= 684π - 512
= 1532.75204 cm³
1 litre = 1000 cm³
⇒ 1.5 litres = 1000 × 1.5 = 1500 cm³
As 1500 < 1532.75204, the volume of water poured into the container is smaller than the empty space available in the cylinder. Therefore, the water will <u>not</u> come over the top of the container.