Geometry help please!!

Mathematics

2 answers:

navik [9.2K]3 years ago

7 0

The first one, 18cm, 6cm, 13cm. First, we need to learn about the triangle equality, it is A + B > C.

So if we take 6+18 it would be 24 which is greater than 13.

Also we have to try 6+13 it would be 19, which is greater than 18.

Then we also have to try 18+13, which is 31. And it is greater than 6.

When it does not fail the triangle equality, it can be a triangle.

Paraphin [41]3 years ago

5 0

I think it is the three one

You might be interested in

Multiply.

Anvisha [2.4K]

Answer:

2x*x

2x*-5

1*x

1*-5

2x²-10x+x-10 add numbers that have similar variables

-2x²-10x+x-10

=[-2x²-9x-10]

8 0

3 years ago

A line that is not parallel nor perpendicular to y=2/4x+1

DENIUS [597]

Answer:

y=2x+1

Step-by-step explanation:

Parallel = gradients are the same

Example: y=2/4x+5

Perpendicular = gradients are the inverse of each other

Example: y= -4/2x+1

Any equation would be correct unless the gradient is 2/4 or -4/2

6 0

3 years ago

F(x)

mina [271]

a) Since both limits are distinct and do not exist, we conclude that x = - 1 is not part of the domain of the rational function.

b) The function $f(x) = \frac{x}{x^{2}+ x}$ is equivalent to the function $g(x) = \frac{1}{x + 1}$ .

<h3>How to determine whether a limit exists or not</h3>

According to theory of limits, a function f(x) exists for x = a if and only if $\lim_{x\to a^{-}} f(x) = \lim_{x \to a^{+}} f(x)$ . This criterion is commonly used to prove continuity of functions.

Rational functions are not continuous for all value of x, as there are x-values that make denominator equal to 0. Based on the figure given below, we have the following lateral limits:

$\lim_{x \to -1^{-}} \frac{x}{x^{2}+x} = - \infty$