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Maurinko [17]
3 years ago
11

Simplify leaving your answer with positive exponents.

Mathematics
1 answer:
vaieri [72.5K]3 years ago
4 0
\bf \left( \cfrac{5m^{\frac{4}{3}}}{n^{\frac{2}{3}}} \right)^{-\frac{2}{3}}\left(\cfrac{m^4}{8n^5}  \right)^{-\frac{4}{3}}\implies 
\left( \cfrac{n^{\frac{2}{3}}}{5m^{\frac{4}{3}}} \right)^{\frac{2}{3}}\left(\cfrac{8n^5}{m^4}  \right)^{\frac{4}{3}}\impliedby  
\begin{array}{llll}
\textit{and now we}\\
\textit{distribute}\\
\textit{the exponent}
\end{array}

\bf \left( \cfrac{n^{\frac{2}{3}\cdot \frac{2}{3}}}{5^{\frac{2}{3}}m^{\frac{4}{3}\cdot \frac{2}{3}}} \right)\left( \cfrac{8^{\frac{4}{3}}n^{5\cdot \frac{4}{3}}}{m^{4\cdot \frac{4}{3}}} \right)\implies \cfrac{n^{\frac{4}{9}}}{5^{\frac{2}{3}}m^{\frac{8}{9}}}\cdot \cfrac{8^{\frac{4}{3}}n^{\frac{20}{3}}}{m^{\frac{16}{3}}}\implies \cfrac{8^{\frac{4}{3}}n^{\frac{4}{9}+\frac{20}{3}}}{5^{\frac{2}{3}}m^{\frac{8}{9}+\frac{16}{3}}}

\bf \cfrac{8^{\frac{4}{3}}n^{\frac{4+60}{9}}}{5^{\frac{2}{3}}m^{\frac{8+48}{9}}}\implies \cfrac{8^{\frac{4}{3}}n^{\frac{64}{9}}}{5^{\frac{2}{3}}m^{\frac{56}{9}}}
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Multiply (6 + 2i)(6 - 2i)
Aleksandr-060686 [28]

Answer:

40

Step-by-step explanation:

(6 + 2i)(6 - 2i)=40

3 0
3 years ago
Read 2 more answers
CAN SOMEONE JUST PLEASE ANSWER THIS ASAP FOR BRAINLIEST!!!
Rom4ik [11]
A=lw
42xy^3=(14xy)l
isolate l
divide both sides by 14xy to isolate l
(42xy^3)/ (14xy)=14xy / 14xy *l
the 14xy in the right cancel out
now you have:
42xy^3/14xy=l
42/14= 3, now just do division of powers for xy
x-x =0x, y^3-y= y^2
therefore the answer is 3y^2
6 0
3 years ago
What is 4²(4²)? <br> 2. 5⁴(5)÷2¹? <br> 3. (5+3)²? <br> Solve the following expressions
Nat2105 [25]

Answer:

256, 3125/2, 64

Step-by-step explanation:

4^2(4^2)=16(16)=256

5^4(5)/2^1=625(5)/2=3125/2

(5+3)^2=8^2=8*8=64

7 0
3 years ago
Another fair dice is rolled 300 times. How many times would you expect it to land with a multiple of three on top? I need help t
ira [324]

Answer:

100 times

Step-by-step explanation:

multiples of 3 on a number cube are 3 and 6

probability of rolling a '3' or '6' is 1/6 + 1/6 = 2/6 or 1/3

1/3 x 300 = 100

7 0
3 years ago
1500 soldiers arrive at a training camp. A few soldiers desert the camp. The drill sergeants divide the remaining soldiers into
iren [92.7K]

Answer:

The number of deserters is 34.

Step-by-step explanation:

We have to calculate the number of desertors in a group of 1500 soldiers.

The sergeant divides in groups of different numbers and count the lefts over.

If he divide in groups of 5, he has on left over. The amount of soldiers grouped has to end in 5 or 0, so the total amount of soldiers has to end in 1 or 6.

If he divide in groups of 7, there are three left over. If we take 3, the number of soldiers gruoped in 7 has to end in 8 or 3. The only numbers bigger than 1400 that end in 8 or 3 and have 7 as common divider are 1428 and 1463.

If we add the 3 soldiers left over, we have 1431 and 1466 as the only possible amount of soldiers applying to the two conditions stated until now.

If he divide in groups of 11, there are three left over. We can test with the 2 numbers we stay:

(1431-3)/11=1428/11=129.82\\\\(1466-3)/11=1463/11=133

As only 1466 gives a possible result (no decimals), this is the amount of soldiers left.

The deserters are 34:

D=1500-1466=34

6 0
3 years ago
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