(1.5)*(2)*(10^(-3)*(10^4) = 3*10^(-3+4) = 3*10^1 = 3*10 = 30 (answer)
Answer:
315
Step-by-step explanation:
Each of the 15 teams plays each of the other 14, for a total of 210 games. However, that count includes both A playing B and B playing A. Hence, if the teams meet 3 times, the total number of games will be 3/2 this amount:
(15)(14)(3/2) = 315 . . . league games
Answer:
values of variables occur at regular frequencies and the mean , median and mode occur at the same point
Step-by-step explanation:
i found this on google sorry if it is a writing prompt so copy/paste if it is
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