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labwork [276]
3 years ago
13

A number x is less than 8

Mathematics
1 answer:
NikAS [45]3 years ago
6 0
X<8
because your number is x, and use < to represent the less sign. Remember, that always have the sign facing out ward when it says x is less than (number)
You might be interested in
-2x-9y=-25 -4x-9y=-23
goldfiish [28.3K]
So to start this off you would add 9y to both sides of the equation and then you regroup it which gives you <span>−2x=−25+9y and then you regroup the terms and get -2x=9y-25 and then you dived both sides by -2 and get x=9y-25/-2 then you simplify and so on 

but at the end you should get x=-1 and y =3
</span><span><span>




</span></span>
8 0
3 years ago
Which quantity is proportional to 40⁄8?
storchak [24]

Answer:

the answer is not on here but it is 5 other than that it might be 5/1.

so D

and B.

Step-by-step explanation:

4 0
3 years ago
What is the answe ?????​
mestny [16]

Answer:

1) The first option

2) -9, -7, 6, 8, 10

3) Rise by 10 degrees

Step-by-step explanation:

Ascending is from smallest to biggest therefore you start with the smallest negative number and end with biggest whole number.

8 0
2 years ago
An energy-efficient lightbulb, taking in 27.0 W of power, can produce the same level of brightness as a conventional lightbulb o
Pavlova-9 [17]

Answer:

$148.4

Step-by-step explanation:

Given:

Power consumed by the energy-efficient lightbulb = 27.0 W = 27.0 × 10⁻³ kW

Power consumed by the conventional lightbulb = 100 W = 100 × 10⁻³ kW

Lifetime of the energy-efficient lightbulb = 10,000 h

Lifetime of the conventional lightbulb = 750 h

Cost of the energy-efficient lightbulb = $4.60 per bulb

Cost of the conventional lightbulb = $0.50 per bulb

Energy cost = $0.20 per kilowatt-hour

Now,

The total cost of  energy-efficient lightbulb for 10,000 hours

= cost of bulb + energy cost

= $4.60 + ( 27.0 × 10⁻³ kW × $0.20 kW/h × 10,000 h)

= $4.60 + $54

= $58.60

Now,

For the life of 10,000 hours number of conventional bulbs required

= \frac{\textup{Total lifetime required}}{\textup{Lifetime per bulb}}

= \frac{\textup{10,000}}{\textup{750}}

= 13.33 ≈ 14 bulbs

Thus,

The total cost of  conventional bulb for 10,000 hours

= cost of bulb + energy cost

= ( $0.50 × 14 ) + ( 100 × 10⁻³ kW × $0.20 kW/h × 10,000 h)

= $7 + $200

= $207

Therefore,

The total savings = $207 - $58.60 = $148.4

3 0
3 years ago
3x(2+6)+4x5<br> hhghh<br> nhhubhhh
tresset_1 [31]

Hi!

Your answer would be: <em>44.</em>

I'll show you how I did it

_________________________

<em>3(2+6)+4x5</em>

<em>=3x8+4x5</em>

<em>=24+4x5</em>

<em>=24+20</em>

<em>=44</em>

_________________________

Hope this helps!

<em>Yours truly,</em>

<h2><em></em></h2><h2><em>~~~PicklePoppers~~~</em></h2>
6 0
3 years ago
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