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slega [8]
3 years ago
5

i need to find the equation of the line that has the same y intercept as the line y-8x+3=0 and is parallel to the line 4x-9y=1

Mathematics
1 answer:
loris [4]3 years ago
5 0

Answer:


Step-by-step explanation:

<u>How do you find the equation of a line parallel to another line? </u>

<em>Method 1:</em> Using Slope Intercept Form

Substitute the slope from original line (3 in this case) into the equation of the line y = 3x + b.

Substitute the given point (1,7) into the x and y values 7 = 3(1) + b.

Solve for b (the y-intercept)

Substitute this value for 'b' in the slope intercept form equation y = 3x + 4.

<u>How do you find the Y intercept of a parallel line? </u>

Step 1: Find the slope of the line. To find the slope of the given line we need to get the line into slope-intercept form (y = mx + b), which means we need to solve for y: The slope of the line 3x – 5y = 9 is m = 3/5. Therefore, the slope of the line parallel to this line would have to be m = 3/5.

You might be interested in
<img src="https://tex.z-dn.net/?f=0.6%20%5Csqrt%7B33.54%7D%20" id="TexFormula1" title="0.6 \sqrt{33.54} " alt="0.6 \sqrt{33.54}
ki77a [65]

0.6\sqrt{33.54}

=5.79137

0.6*5.79137

=3.4

Hope this helps!

Thanks!

-Charlie

6 0
3 years ago
Please can someone please help me
antoniya [11.8K]

Answer:

544 cm²

Step-by-step explanation:

hello,

to find the tsa of a rectangular prism, you use:

tsa = 2 ( lw + lh + wh )

in this case, l = 16 cm, w = 6 cm and h = 8 cm.

knowing these informations, you can proceed with using the formula.

tsa = 2 [ ( 16*6) + ( 16*8 ) + ( 6*8) ]

= 2 [ 96 + 128 + 48 ]

= 2 ( 272 )

= 544 cm²

please try to understand how i worked this out, and do let me know if you have any questions.

have a great day! thank you!

5 0
2 years ago
Square root of 202!!!!!!!!!!!!!! I need help
Goshia [24]

Answer:

approximately 14.2127 but it could also be simplified to the square root of 2 times the square root of 101

6 0
3 years ago
Read 2 more answers
1. as.at<br>2. (a/b)2 (a/b)<br>8<br>3. (3)-5<br>4. (x/y)"<br>5. (2m4n3)5<br>​
Nikolay [14]
1- I didn't understand it

2).. (a/b)² (a/b)⁸

= (a/b)²+⁸ = (a/b)¹⁰

3) 3-⁵ = 1/3⁵ = 1/243

4) (x/y)"

d/dx (x/y) = (1/y)
d/dx (1/y) = 0

5) (2m⁴n³)⁵

= 2⁵ × (m⁴)⁵ × (n³)⁵

= 32 × m²⁰ × n¹⁵

= 32m²⁰n¹⁵
5 0
2 years ago
For the triangles described, which of the following statements must be true? In triangle DEF, DE=8 in., DF=23 in., and ∡D=16°. I
Temka [501]

Answer:

∠Q≅∠F

Step-by-step explanation:

Two triangles are said to be congruent if all the three sides of the triangles are equal and all the three angles are equal.

Given that: In triangle DEF, DE=8 in., DF=23 in., and ∡D=16°. In triangle PQR, PQ=23 in., PR=8 in., and ∡P=16°.

Hence we can say that ΔDEF is congruent to ΔPQR. According to the side-angle-side (SAS) triangle congruence theorem: If two sides and the included angle of one triangle are equal to two sides and the included angle of another triangle, the triangles are congruent.

Therefore:

DF = PQ, DE = PR, EF = RQ, ∠D = ∠P, ∠E = ∠R and ∠F = ∠Q

7 0
3 years ago
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