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3 years ago

i need to find the equation of the line that has the same y intercept as the line y-8x+3=0 and is parallel to the line 4x-9y=1

Mathematics

1 answer:

loris [4]3 years ago

5 0

Answer:

Step-by-step explanation:

How do you find the equation of a line parallel to another line?

Method 1: Using Slope Intercept Form

Substitute the slope from original line (3 in this case) into the equation of the line y = 3x + b.

Substitute the given point (1,7) into the x and y values 7 = 3(1) + b.

Solve for b (the y-intercept)

Substitute this value for 'b' in the slope intercept form equation y = 3x + 4.

How do you find the Y intercept of a parallel line?

Step 1: Find the slope of the line. To find the slope of the given line we need to get the line into slope-intercept form (y = mx + b), which means we need to solve for y: The slope of the line 3x – 5y = 9 is m = 3/5. Therefore, the slope of the line parallel to this line would have to be m = 3/5.

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How do I solve 26.49 + s =44.31

Nookie1986 [14]

You take 44.31-26.49=s

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3 years ago

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You have received an order of 100 robotic resistance spot welders which contains 5 defective welders. You randomly select 15 wel

erica [24]

Answer:

$P(X = 0) = h(0,100,15,5) = \frac{C_{5,0}*C_{95,15}}{C_{100,15}} = 0.4357$

$P(X = 1) = h(1,100,15,5) = \frac{C_{5,1}*C_{95,14}}{C_{100,15}} = 0.4034$

$P(X = 2) = h(2,100,15,5) = \frac{C_{5,2}*C_{95,13}}{C_{100,15}} = 0.1377$

$P(X = 3) = h(3,100,15,5) = \frac{C_{5,3}*C_{95,12}}{C_{100,15}} = 0.0216$

$P(X = 4) = h(4,100,15,5) = \frac{C_{5,4}*C_{95,11}}{C_{100,15}} = 0.0015$

$P(X = 5) = h(5,100,15,5) = \frac{C_{5,5}*C_{95,10}}{C_{100,15}} = 0.00004$

b) 0.154% probability that there are at least 4 defective welders in the sample

Step-by-step explanation:

The welders are chosen without replacement, so the hypergeometric distribution is used.

The probability of x sucesses is given by the following formula:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

In which

x is the number of sucesses.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

In this question:

100 welders, so $N = 100$

Sample of 15, so $n = 15$

In total, 5 defective, so $k = 5$

(a) Determine the PMF of the number of defective welders in your sample?

There are 5 defective, so this is P(X = 0) to P(X = 5). Then

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

$P(X = 0) = h(0,100,15,5) = \frac{C_{5,0}*C_{95,15}}{C_{100,15}} = 0.4357$

$P(X = 1) = h(1,100,15,5) = \frac{C_{5,1}*C_{95,14}}{C_{100,15}} = 0.4034$

$P(X = 2) = h(2,100,15,5) = \frac{C_{5,2}*C_{95,13}}{C_{100,15}} = 0.1377$

$P(X = 3) = h(3,100,15,5) = \frac{C_{5,3}*C_{95,12}}{C_{100,15}} = 0.0216$

$P(X = 4) = h(4,100,15,5) = \frac{C_{5,4}*C_{95,11}}{C_{100,15}} = 0.0015$

$P(X = 5) = h(5,100,15,5) = \frac{C_{5,5}*C_{95,10}}{C_{100,15}} = 0.00004$

(b) Determine the probability that there are at least 4 defective welders in the sample?

$P(X \geq 4) = P(X = 4) + P(X = 5) = 0.0015 + 0.00004 = 0.00154$

0.154% probability that there are at least 4 defective welders in the sample

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3 years ago

Lisa lives 7 miles from school. She bikes to school and back every day. How many miles does she bike in 1 school week

drek231 [11]

Answer:

Step-by-step explanation:

You do 14*5 because she bikes 7 miles to school and 7 miles back, then a school week is 5 days

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Solve each equation with the quadratic formula

sp2606 [1]

First step, list your A,B,C’s.
A=5
B=-9
C=-116

The quadratic formula is:
y= -b +/- the square root of b^2-4(a)(c)
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2a

^ all of that is divided by 2(a)

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lutik1710 [3]

Answer:

Step-by-step explanation:

As x gets bigger or smaller, y approaches negative infinity

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