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shepuryov [24]
3 years ago
9

For 12-13, use the figure. A bike path crosses a road as shown. Solve for each indicated angle or variable.

Mathematics
1 answer:
Volgvan3 years ago
6 0

Answer:

x=21° and ∠KMH=96°

Step-by-step explanation:

From the given information that a bike path crosses a road and the given figure, we get

∠GMH=∠KMI=84°(Vertically opposite angles)

⇒4x=84°

⇒x=21°

therefore, the value of ∠GMH=4x=4(21)=84°

Now, ∠KMH+∠KMI=180°( Linear pair)

⇒∠KMH+84°=180°

⇒∠KMH=180-84

⇒∠KMH=96°

Thus, the value of ∠KMH is 96°

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Use the distributive property to create an equivalent expression to the equation 9(2j + 5j).
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Answer:

63 Hope this helps you and everyone else :)

Step-by-step explanation:

First, multiply 9x2 to get 18. Then, multiply 9x5 to get 45. Finally add both numbers to get 63.

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Create a number line to illustrate the following operations and find the solution.
irakobra [83]

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What is 2M? <br> Is anyone good at Matrices?
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It's the first one

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What is the square root of m^6?
Nastasia [14]
Answer:
If m is nonnegative (ie not allowed to be negative), then the answer is m^3
If m is allowed to be negative, then the answer is either |m^3| or |m|^3

==============================

Explanation:

There are two ways to get this answer. The quickest is to simply divide the exponent 6 by 2 to get 6/2 = 3. This value of 3 is the final exponent over the base m. Why do we divide by 2? Because the square root is the same as having an exponent of 1/2 = 0.5, so
sqrt(m^6) = (m^6)^(1/2) = m^(6*1/2) = m^(6/2) = m^3
This assumes that m is nonnegative. 

---------------------------

A slightly longer method is to break up the square root into factors of m^2 each and then apply the rule that sqrt(x^2) = x, where x is nonnegative

sqrt(m^6) = sqrt(m^2*m^2*m^2)
sqrt(m^6) = sqrt(m^2)*sqrt(m^2)*sqrt(m^2)
sqrt(m^6) = m*m*m
sqrt(m^6) = m^3
where m is nonnegative

------------------------------

If we allow m to be negative, then the final result would be either |m^3| or |m|^3. 

The reason for the absolute value is to ensure that the expression m^3 is nonnegative. Keep in mind that m^6 is always nonnegative, so sqrt(m^6) is also always nonnegative. In order for sqrt(m^6) = m^3 to be true, the right side must be nonnegative.

Example: Let's say m = -2
m^6 = (-2)^6 = 64
sqrt(m^6) = sqrt(64) = 8
m^3 = (-2)^3 = -8
Without the absolute value, sqrt(m^6) = m^3 is false when m = -2

4 0
4 years ago
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