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AlekseyPX
3 years ago
14

PLEASE HELPPPP !!!!!!!!!

Mathematics
2 answers:
Brilliant_brown [7]3 years ago
3 0

Answer:

negative 7

Step-by-step explanation

malfutka [58]3 years ago
3 0

Answer:

x=-7

Step-by-step explanation:

3/4(x+21)=10 1/2

3/4x+15 3/4 = 10 1/2

(I put them in improper form)

3/4x+63/4 = 42/4

3/4x=-5.25

divide -5.25 by 3/4= x=-7

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WILL GIVE BRAINLIEST TO PERSON THAT IS CORRECT!!!!
vekshin1
The answer is the third one!!
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7 0
3 years ago
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Can I get an assist...
DerKrebs [107]

Answer:

4; y-5=2(x+3)

Step-by-step explanation:

Question 1: 8y-18=14

8y=32

y=4

Question 2: y-5=2(x-(-3)

y-5=2(x+3)

3 0
3 years ago
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Trigonometry Escape Challenge A
marshall27 [118]

Answer:

B

Step-by-step explanation:

5 0
3 years ago
What is the value of 4+(8*2)-3+5
Fed [463]
Hello there!

You have to do PEMDAS to solve this problem

Parentheses
Exponents
Multiplication
Division
Addition
Subtraction

We're doing: addition, parentheses , and multiplication!

So, 8(2) = 16, right?

Problem becomes: 4 + (16) - 3 + 5

4 + 16 = 20

Problem becomes: 20 - 3 + 5

20 - 3 = 17

17 + 5 = 22

So, therefore your answer would be: 22

Good luck on your assignment and enjoy your day!

~MeIsKaitlyn:)
3 0
3 years ago
) Beth wants to determine a 99 percent confidence interval for the true proportion p of high school students in the area who att
Lunna [17]

Answer:

n has to be at least 16577.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

Out of n randomly selected students she finds that that exactly half attend their home basketball games.

This means that \pi = 0.5

99% confidence level

So \alpha = 0.01, z is the value of Z that has a pvalue of 1 - \frac{0.01}{2} = 0.995, so Z = 2.575.

About how large would n have to be to get a margin of error less than 0.01 for p

We have to find n for which M = 0.01. So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.01 = 2.575\sqrt{\frac{0.5*0.5}{n}}

0.01\sqrt{n} = 2.575*0.5

\sqrt{n} = \frac{2.575*0.5}{0.01}

(\sqrt{n})^2 = (\frac{2.575*0.5}{0.01})^2

n = 16576.6

Rounding up

n has to be at least 16577.

6 0
3 years ago
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