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3 years ago

1.98 subtracted by 0.99

Mathematics

2 answers:

dezoksy [38]3 years ago

6 0

Answer:

0.99

Step-by-step explanation:

Basically take of the decimal points and subtract them as normal then add it back in . Or think about it as money .

Oksana_A [137]3 years ago

5 0

Answer:

0.99

Step-by-step explanation:

1.98 - 0.99 is 0.99.

Easy.

Just do it like you would any other problem.

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Given m||n, find the value of x.<br> +<br> x<br> m<br> 60°

VashaNatasha [74]

Answer:

X = 60° (corresponding angles are equal )

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What is the value of the 8 in the number 2.387

tamaranim1 [39]

Answer:

Step-by-step explanation:

If the point represents decimal, the position of number 8 is

hundredth.

But if represents Thousands the position of number 8 is

tens

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3 years ago

Read 2 more answers

I feel 12 less than 4 times a number is 8, the number is 5. Write a different sentence where the unknown number is also 5.

Lyrx [107]

9 less than 3 times a number is 6

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3 years ago

the perimeter of a rectangle is 132 m. the length is 2 meters more than 3 times the width. find the dimensions of the rectangle

Anon25 [30]

2l + 2w = 132
l = 3w + 2

2(3w+2)+2w=132
6w + 4 + 2w = 132
8w + 4 = 132
8w = 128
w = 16

l = 3(16) + 2
l = 48 + 2
l = 50

2(50) + 2(16) __ 132
100 + 32 = 132

7 0

3 years ago

Indicate the general rule for the arithmetic sequence with a3 = -12 and a8 = -37

Mandarinka [93]

Answer:

The general rule is $a_n = -2 - 5(n-1)$

Step-by-step explanation:

Arithmetic sequence:

In an arithmetic sequence, the difference between consecutive terms is always the same, and this difference is called common difference.

The general rule of an arithmetic sequence is given by:

$a_{n} = a_1 + (n-1)d$

In which $a_1$ is the first term and d is the common difference.

We can also find the nth term as a function of a term m, using:

$a_n = a_m + (n-m)d$

a3 = -12 and a8 = -37

First we find the common difference. So

$a_n = a_m + (n-m)d$

$a_8 = a_3 + (8-3)d$

$-37 = -12 + 5d$

$5d = -25$

$d = -\frac{25}{5}$

$d = -5$

$a_n = a_1 - 5(n-1)$

Finding the first term:

$a_n = a_1 - 5(n-1)$

Since $a_3 = -12$

$a_n = a_1 - 5(n-1)$

$a_3 = a_1 - 5(3-1)$

$a_1 = a_3 + 10 = -12 + 10 = -2$

So the general rule is:

$a_n = a_1 - 5(n-1)$

$a_n = -2 - 5(n-1)$

6 0

3 years ago