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aivan3 [116]
3 years ago
10

1.98 subtracted by 0.99

Mathematics
2 answers:
dezoksy [38]3 years ago
6 0

Answer:

0.99

Step-by-step explanation:

Basically take of the decimal points and subtract them as normal then add it back in . Or think about it as money .

Oksana_A [137]3 years ago
5 0

Answer:

0.99

Step-by-step explanation:

1.98 - 0.99 is 0.99.

Easy.

Just do it like you would any other problem.

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on the same bus, 1/3 of the French speakers can also speak German. how many people can speak both German and French
Alenkinab [10]
It's easy if you just break it into pieces...

1/3 OF the 4/9 French OF people on the bus (27) also speak German.

Of= Multiply

1/3*4/9*27/1=4 speak French AND German




3 0
3 years ago
A car travels 58.8 kilometers in 2.6 hours. What is the car's average speed?
NISA [10]

Answer:

22.6 km/hr

Step-by-step explanation:

58.8/2.6=22.6

7 0
3 years ago
Read 2 more answers
A grocer has 2 kinds of tea, one that sells for $8.00 per pound and the other that sells for $6.00 per pound. How many pounds of
Brilliant_brown [7]

Answer:

35 pounds of $8.00 tea and 15 pounds of $6.00 tea

Step-by-step explanation:

Let x represent the pounds of tea of the $8 kind. 8x would represent the total cost of that type of tea. We can also say 50 - x is the pounds of tea of the $6 kind, so 6(50 - x) is the total cost of that type of tea. 50 * 7.4 represents the total cost of all the tea, and the expression 8x + 6(50 -x) would also represent the same thing. We can write this as an equation,

8x + 6(50 -x) = 50 * 7.4

simplify,

8x + 300 - 6x = 370

2x + 300 = 370

and solve.

2x = 70

x = 35

This means there is 35 pounds of the $8 kind.

We can subtract that from 50 to find,

50 - 35 = 15,

15 pounds is the amount of the $6 kind.

3 0
2 years ago
Read 2 more answers
How to solve logarithmic equations as such
Serga [27]

\bf \textit{exponential form of a logarithm} \\\\ \log_a b=y \implies a^y= b\qquad\qquad a^y= b\implies \log_a b=y \\\\\\ \begin{array}{llll} \textit{Logarithm of exponentials} \\\\ \log_a\left( x^b \right)\implies b\cdot \log_a(x) \end{array} ~\hspace{7em} \begin{array}{llll} \textit{Logarithm Cancellation Rules} \\\\ log_a a^x = x\qquad \qquad \stackrel{\textit{we'll use this one}}{a^{log_a x}=x} \end{array} \\\\[-0.35em] \rule{34em}{0.25pt}

\bf \log_2(x-1)=\log_8(x^3-2x^2-2x+5) \\\\\\ \log_2(x-1)=\log_{2^3}(x^3-2x^2-2x+5) \\\\\\ \log_{2^3}(x^3-2x^2-2x+5)=\log_2(x-1) \\\\\\ \stackrel{\textit{writing this in exponential notation}}{(2^3)^{\log_2(x-1)}=x^3-2x^2-2x+5}\implies (2)^{3\log_2(x-1)}=x^3-2x^2-2x+5

\bf (2)^{\log_2[(x-1)^3]}=x^3-2x^2-2x+5\implies \stackrel{\textit{using the cancellation rule}}{(x-1)^3=x^3-2x^2-2x+5} \\\\\\ \stackrel{\textit{expanding the left-side}}{x^3-3x^2+3x-1}=x^3-2x^2-2x+5\implies 0=x^2-5x+6 \\\\\\ 0=(x-3)(x-2)\implies x= \begin{cases} 3\\ 2 \end{cases}

5 0
3 years ago
A rectangular prism has a volume of 1,500
goblinko [34]

Answer:

1500 = 748h

Step-by-step explanation:

Data:

l=34, w=32

Volume=1500

Write an equation of volume of a rectangular prism:

Volume= L x W x H

Substitute Values:

1500=34 x22 x h

Simplify:

1500=748h

7 0
3 years ago
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