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BigorU [14]
3 years ago
15

The standard form of the equation that represents the number of quarters, q, and the number of dimes, d, that Austin has in his

piggy bank is 5q + 2d = 270. Explain what the intercepts mean in terms of the context and how to find them.
Mathematics
2 answers:
vazorg [7]3 years ago
8 0

The standard form of the equation that represents the number of quarters, q, and the number of dimes, d, that Austin has in his piggy bank is 5q + 2d = 270. This can be change to slope intercept form to see the clearer picture. By dividing the whole equation by 2, so the equation become d= -2.5q + 135.

<span>This means that Austin has initially 135 dimes in his piggy bank and he is losing 2.5 dimes per quater</span>

Mice21 [21]3 years ago
6 0

Answer:

Sample response:  To find one intercept, let d = 0 in the equation and solve for q. To find the other intercept, let q = 0 in the equation and solve for d. The intercepts mean that the bank could be filled with 54 quarters and no dimes, or 135 dimes and no quarters.

Step-by-step explanation:

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The y-intercept of a function is the point where the graph crosses the \mathbf{y = x^3 + 2x^2 - 193x - 270 }

  • The factors of the Jared's graph are: (x - 10), (x + 3) and (x + 9)
  • The y-intercept is -13.5
  • The standard equation of the function is: \mathbf{y = x^3 + 2x^2 - 193x - 270 }

<u>(a) The factors</u>

First, we write out the points where the function cross the x-axis.

The points are:

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\mathbf{x = -9}

Equate the above points to 0

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<u>(b) The y-intercept</u>

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From the attached graph, the graph crosses the y-axis at -13.5.

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In (a), we have:

\mathbf{x -10 = 0}

\mathbf{x +3 = 0}

\mathbf{x +9 = 0}

Multiply the above equations

\mathbf{(x - 10) \times (x + 3) \times (x + 9) = 0 \times 0 \times 0}

\mathbf{(x - 10) \times (x + 3) \times (x + 9) = 0 }

Expand

\mathbf{(x - 10) \times (x^2 + 3x + 9x + 27) = 0 }

\mathbf{(x - 10) \times (x^2 + 12x + 27) = 0 }

Expand

\mathbf{x^3 + 12x^2 + 27x - 10x^2 - 220x - 270 = 0 }

Collect like terms

\mathbf{x^3 + 12x^2 - 10x^2+ 27x  - 220x - 270 = 0 }

\mathbf{x^3 + 2x^2 - 193x - 270 = 0 }

Replace 0 with y

\mathbf{y = x^3 + 2x^2 - 193x - 270 }

Hence, the standard form is: \mathbf{y = x^3 + 2x^2 - 193x - 270 }

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