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2 years ago

If a pair of standard dice are rolled, what is the probability that the sum will be less than 5?

Mathematics

2 answers:

Komok [63]2 years ago

5 0

Answer:

Probability= No. of favorable outcomes/ total no. of outcomes

= 4/6 Since below 5 will be 4

and we need to simplify= 2/3

Step-by-step explanation:

astra-53 [7]2 years ago

5 0

Answer: the answer is 1/6

Step-by-step explanation:

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BRAINLIEST ASAP!!!

Anarel [89]

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In 9x^2 - 16x + 60 = 0, a = 9, b = -16, c = 60
so b2 - 4ac =
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Part B: Solve 4x^2 + 8x - 5 = 0
What would make 8? (5×2)-2 = 8, so:
(2x+5)(2x-1) = 0
2x+5 = 0
2x = -5
x = -5/2
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2x = 1
x = +1/2
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kati45 [8]

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Step-by-step explanation:

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3 years ago

Express 90 as the product of its prime factors,<br><br> Write the prime factors in ascending order

AysviL [449]

90 = 2 * 3 * 3 * 5 just that

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2 years ago

If (a+b)^2=54, and (a-b)^=46, then a^2+b^2=?

erastovalidia [21]

$(a+b)^2 =a^2 +b^2 + 2ab = 54~~~.....(i)\\\\(a-b)^2 = a^2 +b^2 -2ab = 46~~~.....(i)\\\\\\(i)+(ii):\\\\(a+b)^2 +(a-b)^2 = 54+46\\\\\implies a^2 +b^2 + 2ab + a^2 +b^2 - 2ab =100\\\\\implies 2a^2 +2b^2 =100\\\\ \\\implies 2(a^2 +b^2) =100\\\\\implies a^2 +b^2 = \dfrac{100}2 = 50$

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2 years ago

8 ÷ 3/5 Equals? I need this quickly.

cricket20 [7]

Answer:

= 40/3 = 13 1/3

Step-by-step explanation:

8/1 ÷ 3/5 = 8/1 x 5/3

8 x 5 = 40

1 x 3 = 3

= 40/3 = 13 1/3

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