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Serga [27]
3 years ago
11

What is the slope of the line that contains the points (-2, 7) and (2, 3)?

Mathematics
2 answers:
CaHeK987 [17]3 years ago
7 0
-1 i hope this helps
AleksAgata [21]3 years ago
6 0

Answer:

-1

Step-by-step explanation:

We can use the slope formula to find the slope

m = ( y2-y1)/(x2-x1)

    = ( 3-7)/(2- -2)

   = (3-7)/(2+2)

    = -4/4

   = -1

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Answer:

1. Arthur is about 54 meters away from Cameron.

2. Jamie is about 56 meters away from Cameron.

3. Arthur is closer to Cameron.

Step-by-step explanation:

We have been given the locations of Cameron (70,10), Arthur (20,30) and Jamie (45,60) on the the grid in meters.

1. To find the distances of Arthur and Jamie from Cameron we will use distance formula.

\text{Distance}=\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}

\text{Distance between Cameron and Arthur}=\sqrt{(70-20)^{2}+(10-30)^{2}}

\text{Distance between Cameron and Arthur}=\sqrt{(50)^{2}+(-20)^{2}}

\text{Distance between Cameron and Arthur}=\sqrt{2500+400}

\text{Distance between Cameron and Arthur}=\sqrt{2900}

\text{Distance between Cameron and Arthur}=53.8516480713450403\approx 54

Therefore, the distance Arthur is about 54 meters away from​ Cameron.

2. Let us find the distance between Cameron and Jamie.

\text{Distance between Cameron and Jamie}=\sqrt{(70-45)^{2}+(10-60)^{2}}

\text{Distance between Cameron and Jamie}=\sqrt{(25)^{2}+(-50)^{2}}

\text{Distance between Cameron and Jamie}=\sqrt{625+2500}

\text{Distance between Cameron and Jamie}=\sqrt{3125}

\text{Distance between Cameron and Jamie}=55.9016994374947424\approx 56

Therefore, Jamie is about 56 meters away from​ Cameron.

3. We can see that 56 is greater than 54, therefore, Arthur is closer to Cameron.


4 0
4 years ago
Read 2 more answers
Use the given conditions to write an equation for the line in​ point-slope form and general form. Passing through (8 comma negat
miskamm [114]

Answer:

The answer to your question is   y = -5x + 32          point-slope form

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Step-by-step explanation:

Data

(8, -8)

⊥ x - 5y - 6 = 0

Process

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   x - 5y - 6 = 0

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2.- Get the equation of the new line

          y - y1 = m(x - x1)

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          y + 8 = -5x + 40

          y = -5x + 40 - 8

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Equal to zero to find the general form

         5x + y - 32 = 0      general form

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What are the coordinates of the image of point A after the segment has been dilated by a scale factor of One-fourth with a cente
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Answer:

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Step-by-step explanation:

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