The interval for mean sale price is $582
According to statement
The given rates are 560, 468, 685, 534, 658, 593
Now,
Sample mean = X / n
Put the values in it and then
(560+ 468+ 685+ 534+ 658+ 593) / 6 = 582.1667
and use this formula S = sqrt [ X2 - n 2 / (n-1) ]
and put the values in these and
S = sqrt [ X2 - n 2 / (n-1) ] = 95.97179
So, The interval for mean sale price is $582
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Answer:
the answer is D. 5.6
Step-by-step explanation:
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The expected length of code for one encoded symbol is

where
is the probability of picking the letter
, and
is the length of code needed to encode
.
is given to us, and we have

so that we expect a contribution of

bits to the code per encoded letter. For a string of length
, we would then expect
.
By definition of variance, we have
![\mathrm{Var}[L]=E\left[(L-E[L])^2\right]=E[L^2]-E[L]^2](https://tex.z-dn.net/?f=%5Cmathrm%7BVar%7D%5BL%5D%3DE%5Cleft%5B%28L-E%5BL%5D%29%5E2%5Cright%5D%3DE%5BL%5E2%5D-E%5BL%5D%5E2)
For a string consisting of one letter, we have

so that the variance for the length such a string is

"squared" bits per encoded letter. For a string of length
, we would get
.
A=LW
A divided by W= L divided by W (cancels out)
Answer: A/W = L
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Answer:
<em>This question was previously answered on Brainly...</em>
<em>Be sure to put this into your own words.</em>
<em>Answer: check explanation for the solution
</em>
<em>
</em>
Step-by-step explanation:
<em>
</em>
A business that offers services to people by providing many amusement and fun with gate fees
The algebraic equations to be used is the general linear equation
Y = MX + C
Where
Y = total income or money realised
M = rate or price rate
X = number of goods or services
C = flat rate or gate fees
The business can also operate differently by using exponential equation
A = P(1 + R%)^t
Where
A = profit
P = capital
R = rate
t = time