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lbvjy [14]
3 years ago
13

Simplify the question

Mathematics
1 answer:
Andreyy893 years ago
6 0

Answer:

C (5\sqrt6)

Step-by-step explanation:

Hi there! I'm glad I was able to help you solve this problem!

You can always use a scientific calculator to solve this question, which I did, resulting in 5\sqrt6 ... The calculator however also gave me a decimal number, and that number was 12.247449.

I hope this somewhat helped you! Comment below if you have any other questions!

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Recently, six single-family homes in San Luis Obispo County in California sold at the following prices (in $1,000s): 560, 468, 6
solmaris [256]

The interval for mean sale price is $582

According to statement

The given rates are 560, 468, 685, 534, 658, 593

Now,

Sample mean = X / n

Put the values in it and then

(560+ 468+ 685+ 534+ 658+ 593) / 6 = 582.1667

and use this formula S = sqrt [ X2 - n 2 / (n-1) ]

and put the values in these and

S = sqrt [ X2 - n 2 / (n-1) ] = 95.97179

So, The interval for mean sale price is $582

Learn more about SAMPLE MEAN here

brainly.com/question/16794295

#SPJ4

6 0
2 years ago
Help with this ..............
seropon [69]

Answer:

the answer is D. 5.6

Step-by-step explanation:

EVERYONE LISTEN!!!! PLEASE COPY THIS MESSAGE AND RESEND!!!!

If you know youdeservetodie (that is his brainly username) then report him please, he is sending hurtful comments and threatening my friends. Please all I need you to do is get this message out there, copy this message and tell everyone you know, This bully needs to be stopped!!

8 0
3 years ago
Read 2 more answers
A source of information randomly generates symbols from a four letter alphabet {w, x, y, z }. The probability of each symbol is
koban [17]

The expected length of code for one encoded symbol is

\displaystyle\sum_{\alpha\in\{w,x,y,z\}}p_\alpha\ell_\alpha

where p_\alpha is the probability of picking the letter \alpha, and \ell_\alpha is the length of code needed to encode \alpha. p_\alpha is given to us, and we have

\begin{cases}\ell_w=1\\\ell_x=2\\\ell_y=\ell_z=3\end{cases}

so that we expect a contribution of

\dfrac12+\dfrac24+\dfrac{2\cdot3}8=\dfrac{11}8=1.375

bits to the code per encoded letter. For a string of length n, we would then expect E[L]=1.375n.

By definition of variance, we have

\mathrm{Var}[L]=E\left[(L-E[L])^2\right]=E[L^2]-E[L]^2

For a string consisting of one letter, we have

\displaystyle\sum_{\alpha\in\{w,x,y,z\}}p_\alpha{\ell_\alpha}^2=\dfrac12+\dfrac{2^2}4+\dfrac{2\cdot3^2}8=\dfrac{15}4

so that the variance for the length such a string is

\dfrac{15}4-\left(\dfrac{11}8\right)^2=\dfrac{119}{64}\approx1.859

"squared" bits per encoded letter. For a string of length n, we would get \mathrm{Var}[L]=1.859n.

5 0
3 years ago
A=LW;for L. Solve for the indicated variable. Include all work in the answer.
Otrada [13]
A=LW 
A divided by W= L divided by W (cancels out) 
Answer: A/W = L

Hope this helps! Can I get brainliest? lol
3 0
3 years ago
HELPPPPPP !!! I seriously don't know what to write.
tresset_1 [31]

Answer:

<em>This question was previously answered on Brainly...</em>

<em>Be sure to put this into your own words.</em>

<em>Answer: check explanation for the solution </em>

<em> </em>

Step-by-step explanation:

<em> </em>

A business that offers services to people by providing many amusement and fun with gate fees

The algebraic equations to be used is the general linear equation

Y = MX + C

Where

Y = total income or money realised

M = rate or price rate

X = number of goods or services

C = flat rate or gate fees

The business can also operate differently by using exponential equation

A = P(1 + R%)^t

Where

A = profit

P = capital

R = rate

t = time

3 0
3 years ago
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