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Alchen [17]
3 years ago
10

3.2-9x+7.1-3x= what is the answer

Mathematics
1 answer:
Alex3 years ago
6 0
3.2 -9x+ 7.1 -3x
= (-9x -3x)+ (3.2+ 7.1) (combine like terms)
= -12x+ 10.3

The final answer is -12x+ 10.3~
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Pls help I will give u brainlyist​
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Step-by-step explanation:

2 triangles on top

and the sides with rectangle.

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The equation of line CD is y=3x-3. Write an equation of a line perpendicular to line CD in slop-intercept form that contains poi
Svetradugi [14.3K]
Y = -x/3 + b1 = -3/3 + b              
 substitute values of point1 = -1 + b                  
then reduce2 = b                          
 add one to both sides y = -x/3 + 2
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A stack of cards is numbered 1 to 21. Allison pulls one card from the stack.
Nataly_w [17]
D.) 52%, this is because there are 11 odd numbers for 1 to 21, so the fraction is 11/21, which is approximately 52%
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3 years ago
What is an equation of the line that passes through the points (4, -1) and (-8, -7)?
statuscvo [17]

Answer:

y=-1/2x - 3

I think this is it, its been a while though.

3 0
2 years ago
I need help understanding this ASAP plz, I have a quiz over this next week!!!!
scZoUnD [109]

Answer:

Step-by-step explanation:

With any two points, you can find the line between them with:

y = mx + b\\where\\m = \frac{y_2-y_1}{x_2-x_1}

#1:

(-1, 1) -> (1, 3) m = \frac{3-1}{1-(-1)} = 1, 3 = 1(1) + b, b = 2, y = x + 2

(3, 4) -> (0, 2) m = \frac{4-2}{3-0} = \frac{2}{3}, 2 = \frac{2}{3}(0) + b, y = \frac{2}{3}(x)+2

(0, 1) -> (3, 3) m = \frac{3-1}{3-0} = \frac{2}{3}, 1 = 2/3(0) + b, y = \frac{2}{3}(x) + 1

Lines b and c are parallel because they have the same slopes

#2 is a bit easier

a: 2y = x + 12, y = \frac{1}{2}(x) + 6

b:2y - x = 5, y = \frac{1}{2}(x) + \frac{5}{2}

c: 2y + x = 4, y = \frac{-1}{2}(x) + 2

Since lines a and b have the same slope, they are parallel

#3:

(1, 3), y = 2x - 5

We have to find a line with a slope of 2 that passes through the two points

y = 2x + b\\3 = 2(1) + b\\b = 1\\\\y = 2x + 1

#4:

(-2, 1) , y = -4x + 3

We have to find a line with a slope of-4 that passes through the line

y = -4x + b\\1 = -4(-2) + b\\1 = 8+ b\\b = -7\\y = -4x - 7

#5:

(-2, 3) (1, -1), m = \frac{3-(-1)}{-2-1} = \frac{-4}{3}, 3 = \frac{8}{3} + b, b = \frac{1}{3}, y = \frac{-4x}{3} + \frac{1}{3}

(-3, 1) (1, 4), m = \frac{4-1}{1-(-3)} =\frac{3}{4}, 4 = \frac{3(1)}{4} + b, y = \frac{3}{4}(x) + \frac{13}{4}

(0, 2) (3, -2) m = \frac{2-(-2)}{0-3} = \frac{-4}{3} , 2 = b, y = \frac{-4}{3}(x) + 2

Since lines c and b have negative reciprocal slopes, they are perpendicular

#6:

a: y = -4x + 7

b: x = 4y + 2, y = \frac{x}{4} - \frac{1}{2}

c: -4y + x = 3, y = \frac{x}{4} - \frac{3}{4}

since lines a and c have negative reciprocal slopes, they are perpendicular

6 0
3 years ago
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