Question

-x-2>2(3-x) solve the inequality

Answer 1

$Solution, -x-2>2\left(3-x\right)\quad :\quad \begin{bmatrix}\mathrm{Solution:}\:&\:x>8\:\\ \:\mathrm{Interval\:Notation:}&\:\left(8,\:\infty \:\right)\end{bmatrix}$

$Steps:$

$\mathrm{Expand\:}2\left(3-x\right):\quad 6-2x, -x-2>6-2x$

$\mathrm{Add\:}2\mathrm{\:to\:both\:sides}, -x-2+2>6-2x+2$

$\mathrm{Simplify}, -x>-2x+8$

$\mathrm{Add\:}2x\mathrm{\:to\:both\:sides},-x+2x>-2x+8+2x$

$\mathrm{Simplify}, x>8$

The correct answer is x>8

Hope This Helps!!!