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3 years ago

Emily is making a meal for her family. She uses coconut milk for the dessert she is making.

Mathematics

1 answer:

Artyom0805 [142]3 years ago

3 0

Answer:

576 cm^3

Step-by-step explanation:

Express this volume formula as V = π r^2 h, where the " ^ " symbol indicates exponentiation. Substitute 4 for r (this is half the diameter), 12 cm for h, and 3 for π: V = 3*(4)^2*12 cm^3, or V = 576 cm^3.

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Data collected at Toronto Pearson International Airport suggests that an exponential distribution with mean value 2725hours is a

Ivan

Answer:

a) What is the probability that the duration of a particular rainfall event at this location is at least 2 hours?

We want this probability"

$P(X >2) = 1-P(X\leq 2) = 1-(1- e^{-0.367 *2})=e^{-0.367 *2}= 0.48$

At most 3 hours?

$P(X \leq 3) = F(3) = 1-e^{-0.367*3}= 1-0.333 =0.667$

b) What is the probability that rainfall duration exceeds the mean value by more than 2 standard deviations?

$P(X > 2.725 + 2*5.540) = P(X>13.62) = 1-P(X$

What is the probability that it is less than the mean value by more than one standard deviation?

$P(X$

Step-by-step explanation:

Previous concepts

The exponential distribution is "the probability distribution of the time between events in a Poisson process (a process in which events occur continuously and independently at a constant average rate). It is a particular case of the gamma distribution". The probability density function is given by:

$P(X=x)=\lambda e^{-\lambda x}$

The cumulative distribution for this function is given by:

$F(X) = 1- e^{-\lambda x}, x\ geq 0$

We know the value for the mean on this case we have that :

$mean = \frac{1}{\lambda}$

$\lambda = \frac{1}{Mean}= \frac{1}{2.725}=0.367$

Solution to the problem

Part a

What is the probability that the duration of a particular rainfall event at this location is at least 2 hours?

We want this probability"

$P(X >2) = 1-P(X\leq 2) = 1-(1- e^{-0.367 *2})=e^{-0.367 *2}= 0.48$

At most 3 hours?

$P(X \leq 3) = F(3) = 1-e^{-0.367*3}= 1-0.333 =0.667$

Part b

What is the probability that rainfall duration exceeds the mean value by more than 2 standard deviations?

The variance for the esponential distribution is given by: $Var(X) =\frac{1}{\lambda^2}$

And the deviation would be:

$Sd(X) = \frac{1}{\lambda}= \frac{1}{0.367}= 2.725$

And the mean is given by $Mean = 2.725$

Two deviations correspond to 5.540, so we want this probability:

$P(X > 2.725 + 2*5.540) = P(X>13.62) = 1-P(X$

What is the probability that it is less than the mean value by more than one standard deviation?

For this case we want this probablity:

$P(X$

8 0

3 years ago

159.98 divided by 6 <br><br> ASAPP

ArbitrLikvidat [17]

159.98 divided by 6 is 26.66, hopefully this is correct...

4 0

3 years ago

1/3y+11=1/2y-3<br><br> What is y???

JulijaS [17]

Answer:

y = 84

Step-by-step explanation:

1) add 3 to both sides of your equation to cancel out the -3

end up with: (1/3)y + 14 = (1/2)y

2) multiply both sides of your equation by 2 to cancel out the (1/2)

end up with: (2/3)y + 28 = y

3) subtract (2/3)y from both sides of the equation to cancel out the positive (2/3)y

end up with: 28 = (1/3)y

4) multiply both sides of the equation by 3 to cancel out the (1/3)

end up with: 84 = y

6 0

3 years ago

In a certain Algebra 2 class of 24 students, 9 of them play basketball and 13 of them

marta [7]

Answer:

20/24 or 5/6

for deltamath

7 0

3 years ago

5. Solve using any method.<br> y = -x + 8<br> y=x+4

vlada-n [284]

Answer:

Step-by-step explanation:

$\bold{ELIMINATION\ METHOD}\\\\\left\{\begin{array}{ccc}y=-x+8\\y=x+4&\TEXT{change the signs}\end{array}\right\\\underline{+\left\{\begin{array}{ccc}y=-x+8\\-y=-x-4\end{array}\right}\qquad\text{add both sides of the equations}\\.\qquad0=-2x+4\qquad\text{add}\ 2x\ \text{to both sides}\\.\qquad2x=4\qquad\text{divide both sides by 2}\\.\qquad\boxed{x=2}\\\\\text{Put it to the second equation}\\y=2+4\\\boxed{y=6}$

$\bold{SUBSTITUTION\ METHOD}\\\\\left\{\begin{array}{ccc}y=-x+8&(1)\\y=x+4&(2)\end{array}\right\\\\\text{Substitute (1) to (2)}\\\\-x+8=x+4\qquad\text{subtract 8 from both sides}\\-x=x-4\qquad\text{subtract}\ x\ \text{from both sides}\\-x-x=-4\\-2x=-4\qquad\text{divide both sides by (-2)}\\\boxed{x=2}\\\\\text{Put it to the second equation}\\y=2+4\\\boxed{y=6}$

7 0

3 years ago