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erastova [34]
3 years ago
8

Use the drop downs to answer the following questions of finding the distance from (–6, 2) to the origin. Use (0, 0) as (x1, y1).

d = StartRoot (x 2 minus x 1) squared + (y 2 minus y 1) squared EndRoot What is the difference of the x-coordinates, (x2–x1)? What is the difference of the y-coordinates, (y2–y1)? What is the distance from (–6, 2) to the origin?
Mathematics
2 answers:
kaheart [24]3 years ago
9 0

Answer:

What is the difference of the x-coordinates, (x2–x1)?

-6

What is the difference of the y-coordinates, (y2–y1)?

2

What is the distance from (–6, 2) to the origin?

6.32

scoray [572]3 years ago
7 0

Answer:

6, 2, 6.32.

Step-by-step explanation:

got it right on the instruction in edge :)

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Two Step Inequality Math problems
Iteru [2.4K]

Answer:

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Step-by-step explanation:

7 0
2 years ago
Determine whether each of the following products is rational or irrational.
ankoles [38]

Answer:

-irrational

-rational

-rational

-irrational

__________________________________________________________quick and easy way is to see if the squares are perfect squares, like square root seven is irrational, so the answer is irrational. square root 9 is 3, which is rational, so its rational.

brainliest is appreciated :)

6 0
3 years ago
Which of the following numbers could be the sides of a right triangle. A)8,15,17. B)6,8,12 C)9,11,21 D)4,13,16
ArbitrLikvidat [17]

Answer:

A) 8, 15, 17.

Step-by-step explanation:

Right triangle obey the Pythagorean theorem. Thus, we choose the two smaller numbers (being the cathetus) and if after applying the P. Theorem we get the biggest of each option  (the hypotenuse) that means that those numbers could be the sides of a right triangle.

The Pythagorean theorem states that: a^2+b^2=c^2

Thus:

\sqrt{a^2+b^2}=c

Option A:

\sqrt{8^2+15^2}=17 → 17 = 17 OK!

Option B:

\sqrt{6^2+8^2}  = 10 → 10 ≠ 12 NO

Option C:

\sqrt{9^2+11^2} = [tex]\sqrt{202}[/tex] → \sqrt{202} ≠ 21 NO

Option D:

\sqrt{4^2+13^2} = \sqrt{185} → \sqrt{185} ≠ 16 NO

3 0
3 years ago
A company's stock begins the week with a price of $43.85 per share. THe price changes by +$2.70 each day for the first two days,
mixas84 [53]

Given:

Initial price of the stock=$43.85

Change for the first two days=+$2.70

Change for next two days=-$1.10

Last day=-$4.45

The objective is to find the price at the last day.

Let's take the price at final day as <em>x</em>.

\begin{gathered} x=43.85+2.70+2.70-1.10-1.10-4.45 \\ x=42.6 \end{gathered}

Hence, the price of the stock at the last day is $42.6

5 0
1 year ago
Question 11
PtichkaEL [24]

Answer:

65%

Step-by-step explanation:

5 0
3 years ago
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