Answer:
<em>BC, BD, BQ, CB, CD, CQ, DB, DC, DQ, QB, QC, QD </em>
Step-by-step explanation:
<em>"BC, BD, BQ, CB, CD, CQ, DB, DC, DQ, QB, QC, QD"</em> Are all the possible rays on line c.
Answer:
![t \approx 36.1\,min](https://tex.z-dn.net/?f=t%20%5Capprox%2036.1%5C%2Cmin)
Step-by-step explanation:
The time constant for the isotope decay is:
![\tau = \frac{8\min}{\ln 2}](https://tex.z-dn.net/?f=%5Ctau%20%3D%20%5Cfrac%7B8%5Cmin%7D%7B%5Cln%202%7D)
![\tau \approx 11.542\,min](https://tex.z-dn.net/?f=%5Ctau%20%5Capprox%2011.542%5C%2Cmin)
Now, the decay of the isotope is modelled after the following expression:
![m (t) = m_{o}\cdot e^{-\frac{t}{\tau} }](https://tex.z-dn.net/?f=m%20%28t%29%20%3D%20m_%7Bo%7D%5Ccdot%20e%5E%7B-%5Cfrac%7Bt%7D%7B%5Ctau%7D%20%7D)
The time is now cleared with some algebraic handling:
![\frac{m(t)}{m_{o}} = e^{-\frac{t}{\tau} }](https://tex.z-dn.net/?f=%5Cfrac%7Bm%28t%29%7D%7Bm_%7Bo%7D%7D%20%3D%20e%5E%7B-%5Cfrac%7Bt%7D%7B%5Ctau%7D%20%7D)
![t = -\tau \cdot \ln \frac{m(t)}{m_{o}}](https://tex.z-dn.net/?f=t%20%3D%20-%5Ctau%20%5Ccdot%20%5Cln%20%5Cfrac%7Bm%28t%29%7D%7Bm_%7Bo%7D%7D)
Finally, the time need for the element X to decay to 43 grams is:
![t = - (11.542\,min)\cdot \ln\left(\frac{43\,g}{980\,g} \right)](https://tex.z-dn.net/?f=t%20%3D%20-%20%2811.542%5C%2Cmin%29%5Ccdot%20%5Cln%5Cleft%28%5Cfrac%7B43%5C%2Cg%7D%7B980%5C%2Cg%7D%20%5Cright%29)
![t \approx 36.1\,min](https://tex.z-dn.net/?f=t%20%5Capprox%2036.1%5C%2Cmin)
Answer:
depends on what it is. like is it a dice or something you're pulling out of a bag.
Answer:
84%
Step-by-step explanation:
The percentage of pink shirts
= 9/200 × 100%
= 9/2
= 4.5%
The percentage of orange shirts
= 69/600 × 100%
= 69/6
= 11.5%
The percentage of the shirts which are not pink or orange
= 1 - 4.5% - 11.5%
= 84%
<u>Alternative</u>
Find their common denominator.
9/200
= 9×3 / 200×3
= 27/600
The total percentage of shirts in pink and orange
= (27/600 + 69/600) × 100%
= 96/600 × 100%
= 16%
The percentage of the shirts which are not pink or orange
= 1 - 16%
= 84%