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3 years ago

24 is what percent of 400?

Mathematics

2 answers:

aliya0001 [1]3 years ago

7 0

Answer:

The answer is 6%

lys-0071 [83]3 years ago

5 0

Answer:

Step-by-step explanation:

tell me if I’m wrong lol

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a) If the null hypothesis is true, you'll get a high P-value. b) If the null hypothesis is true, a P-value of 0.01 will oc

maxonik [38]

Answer:

a) If the null hypothesis is true, you'll get a high P-value. (it depends)

b) If the null hypothesis is true, a P-value of 0.01 will occur about 1% of the time. (false)

c) A P-value of 0.90 means that the null hypothesis has a good chance of being true. (not only has a good chance it has strong evidence)

d) A P-value of 0.90 is strong evidence that the null hypothesis is true.(true)

Step-by-step explanation:

Before i answer this question, you need to understand that p-values give you the clues to identify when you can accept the null hypothesis ( null hypothesis is true) and when you can reject the null hypothesis (null hypothesis is not true).

1. When you get a small p-value (typically ≤ 0.05) values that are less or equal to 0.05, for example 0.01, you reject the null hypothesis (null hypothesis is not true)

2. when you get a large p-value (> 0.05) values that are greater than 0.05, for example 0.94, 0.90. you can accept the null hypothesis because indicates weak evidence against the null hypothesis (null hypothesis is true).

This is the explanation:

a) if the null hypothesis is true you`ll get a high p-value only if the p-value is ≥ 0.05

b) if p value is less or equal to 0.05. Null hypothesis is not true.

c) A P-value of 0.90 means that the null hypothesis has a good chance of being true . It not only has a good chance it is strong evidence that null hypothesis is true.

d) A p-value of 0.90 is strong evidence that null hypothesis is true. p-values that are greater than 0.05 you can accept the null hypothesis (null hypothesis is true).

7 0

3 years ago

Price per volleyball if 6 volleyballs cost $18.00? Please I need helpppp

Nastasia [14]

Answer:

The price per volleyball is $3.

Step-by-step explanation:

Divide $18 by 6 for the cost of each volleyball in which your final answer should be $3 per volleyball.

7 0

3 years ago

STOP! DONT SCROLL PAST THIS! I️ NEED YOUR HELP ASAP IM BEGGING YOU!!! What is the slope of the given slide?

mestny [16]

That would be -16.15549...
Hope it helps!

3 0

4 years ago

Read 2 more answers

Geometry help will give brainliest

LUCKY_DIMON [66]

You did the equation a little wrong. It is A^2 + B^2 = 10^2

4 0

3 years ago

Find the exact value of the expression. tan( sin−1 (2/3)− cos−1(1/7))

Sonja [21]

Answer:

$\tan(a-b)=\frac{2\sqrt{5}-20\sqrt{3}}{5+8\sqrt{15}}$

Step-by-step explanation:

I'm going to use the following identity to help with the difference inside the tangent function there:

$\tan(a-b)=\frac{\tan(a)-\tan(b)}{1+\tan(a)\tan(b)}$

Let $a=\sin^{-1}(\frac{2}{3})$ .

With some restriction on $a$ this means:

$\sin(a)=\frac{2}{3}$

We need to find $\tan(a)$ .

$\sin^2(a)+\cos^2(a)=1$ is a Pythagorean Identity I will use to find the cosine value and then I will use that the tangent function is the ratio of sine to cosine.

$(\frac{2}{3})^2+\cos^2(a)=1$

$\frac{4}{9}+\cos^2(a)=1$

Subtract 4/9 on both sides:

$\cos^2(a)=\frac{5}{9}$

Take the square root of both sides:

$\cos(a)=\pm \sqrt{\frac{5}{9}}$

$\cos(a)=\pm \frac{\sqrt{5}}{3}$

The cosine value is positive because $a$ is a number between $-\frac{\pi}{2}$ and $\frac{\pi}{2}$ because that is the restriction on sine inverse.

So we have $\cos(a)=\frac{\sqrt{5}}{3}$ .

This means that $\tan(a)=\frac{\frac{2}{3}}{\frac{\sqrt{5}}{3}}$ .

Multiplying numerator and denominator by 3 gives us:

$\tan(a)=\frac{2}{\sqrt{5}}$

Rationalizing the denominator by multiplying top and bottom by square root of 5 gives us:

$\tan(a)=\frac{2\sqrt{5}}{5}$

Let's continue on to letting $b=\cos^{-1}(\frac{1}{7})$ .

Let's go ahead and say what the restrictions on $b$ are.

$b$ is a number in between 0 and $\pi$ .

So anyways $b=\cos^{-1}(\frac{1}{7})$ implies $\cos(b)=\frac{1}{7}$ .

Let's use the Pythagorean Identity again I mentioned from before to find the sine value of $b$ .

$\cos^2(b)+\sin^2(b)=1$

$(\frac{1}{7})^2+\sin^2(b)=1$

$\frac{1}{49}+\sin^2(b)=1$

Subtract 1/49 on both sides:

$\sin^2(b)=\frac{48}{49}$

Take the square root of both sides:

$\sin(b)=\pm \sqrt{\frac{48}{49}$

$\sin(b)=\pm \frac{\sqrt{48}}{7}$

$\sin(b)=\pm \frac{\sqrt{16}\sqrt{3}}{7}$

$\sin(b)=\pm \frac{4\sqrt{3}}{7}$

So since $b$ is a number between $0$ and $\pi$ , then sine of this value is positive.

This implies:

$\sin(b)=\frac{4\sqrt{3}}{7}$

So $\tan(b)=\frac{\sin(b)}{\cos(b)}=\frac{\frac{4\sqrt{3}}{7}}{\frac{1}{7}}$ .

Multiplying both top and bottom by 7 gives:

$\frac{4\sqrt{3}}{1}= 4\sqrt{3}$ .

Let's put everything back into the first mentioned identity.

$\tan(a-b)=\frac{\tan(a)-\tan(b)}{1+\tan(a)\tan(b)}$

$\tan(a-b)=\frac{\frac{2\sqrt{5}}{5}-4\sqrt{3}}{1+\frac{2\sqrt{5}}{5}\cdot 4\sqrt{3}}$

Let's clear the mini-fractions by multiply top and bottom by the least common multiple of the denominators of these mini-fractions. That is, we are multiplying top and bottom by 5:

$\tan(a-b)=\frac{2 \sqrt{5}-20\sqrt{3}}{5+2\sqrt{5}\cdot 4\sqrt{3}}$

$\tan(a-b)=\frac{2\sqrt{5}-20\sqrt{3}}{5+8\sqrt{15}}$

4 0

3 years ago