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4 years ago

Complete the following table with the properties used to solve 4(x+3) = 20

Mathematics

1 answer:

STALIN [3.7K]4 years ago

8 0

Answer:

4(x+3) = 20

Distrbute

4x+12 = 20

-12 from both sides

4x = 8

divide both sides by 4

x = 2

Step-by-step explanation:

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20 points

densk [106]

Answer:

Step-by-step explanation:

A polynomial is an expression consisting of variables and coefficients, that involves only the operations of addition, subtraction, multiplication, and non-negative integer exponents of variables.

$A.\ \dfrac{7}{x^2}=7x^{-2}\qquad\bold{NOT}\\\\B.\ x-\sqrt7\qquad\bold{YES}\\\\C.\ \dfrac{7}{\sqrt{x}}=7x^{-\frac{1}{2}}\qquad\bold{NOT}\\\\D.\ \sqrt{7x}=\sqrt7\cdot\sqrt{x}=\sqrt7 x^\frac{1}{2}\qquad\bold{NOT}$

5 0

3 years ago

A university found that 20% of its students withdraw without completing the introductory statistics course. Assume that 20 stude

Mkey [24]

Answer:

(a) Probability that 2 or fewer will withdraw is 0.2061.

(b) Probability that exactly 4 will withdraw is 0.2182.

(c) Probability that more than 3 will withdraw is 0.5886.

(d) The expected number of withdrawals is 4.

Step-by-step explanation:

We are given that a university found that 20% of its students withdraw without completing the introductory statistics course.

Assume that 20 students registered for the course.

The above situation can be represented through binomial distribution;

$P(X =r) = \binom{n}{r} \times p^{r} \times (1-p)^{n-r};x=0,1,2,3,......$

where, n = number of trials (samples) taken = 20 students

r = number of success

p = probability of success which in our question is probability

that students withdraw without completing the introductory

statistics course, i.e; p = 20%

Let X = Number of students withdraw without completing the introductory statistics course

So, X ~ Binom(n = 20 , p = 0.20)

(a) Probability that 2 or fewer will withdraw is given by = P(X $\leq$ 2)

P(X $\leq$ 2) = P(X = 0) + P(X = 1) + P(X = 2)

= $\binom{20}{0} \times 0.20^{0} \times (1-0.20)^{20-0}+ \binom{20}{1} \times 0.20^{1} \times (1-0.20)^{20-1}+ \binom{20}{2} \times 0.20^{2} \times (1-0.20)^{20-2}$

= $1 \times1 \times 0.80^{20}+ 20 \times 0.20^{1} \times 0.80^{19}+ 190\times 0.20^{2} \times 0.80^{18}$

= 0.2061

(b) Probability that exactly 4 will withdraw is given by = P(X = 4)

P(X = 4) = $\binom{20}{4} \times 0.20^{4} \times (1-0.20)^{20-4}$

= $4845\times 0.20^{4} \times 0.80^{16}$

= 0.2182

(c) Probability that more than 3 will withdraw is given by = P(X > 3)

P(X > 3) = 1 - P(X $\leq$ 3) = 1 - P(X = 0) - P(X = 1) - P(X = 2) - P(X = 3)

= $1-(\binom{20}{0} \times 0.20^{0} \times (1-0.20)^{20-0}+ \binom{20}{1} \times 0.20^{1} \times (1-0.20)^{20-1}+ \binom{20}{2} \times 0.20^{2} \times (1-0.20)^{20-2}+\binom{20}{3} \times 0.20^{3} \times (1-0.20)^{20-3})$

= $1-(1 \times1 \times 0.80^{20}+ 20 \times 0.20^{1} \times 0.80^{19}+ 190\times 0.20^{2} \times 0.80^{18}+1140\times 0.20^{3} \times 0.80^{17})$

= 1 - 0.4114 = 0.5886

(d) The expected number of withdrawals is given by;

E(X) = $n\times p$

= $20 \times 0.20$ = 4 withdrawals

3 0

4 years ago

What is 25+x= 50 solve for x

arsen [322]

25+x = 50
x = 50-25
x = 25

8 0

4 years ago

What is the area of the circle in terms of pi? diameter of 4.1m

Black_prince [1.1K]

13.20254313. Pi(2.05)^2. 4.1÷2(for the radius)=2.05.Square it and multiply by Pi. a=pi(r)^2

5 0

3 years ago

Solve for x: 2x^2+4x-16+=0

ella [17]

$2x^2+4x-16=0|:2\\
x^2+2x-8=0\\
\Delta=36\Rightarrow\sqrt{\Delta}=6\\
x_1=\frac{-b+\sqrt{\Delta}}{2a}\ \vee\ x_=\frac{-b-\sqrt{\Delta}}{2a}\\
x_1=2\ \vee\ x_2=-4$

8 0

3 years ago

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