At what value of x do the graphs of the equation below intersect ? 2x-y=6 5x+10y=-10

Mathematics

1 answer:

Y_Kistochka [10]3 years ago

5 0

Answer:

x = 2

Step-by-step explanation:

Solve the two equations simultaneously....whereby you substitute y = 2x - 6 from the above equation into the second equation...

where...; 5x + 10(2x - 6) = -10

5x + 20x - 60 = -10...then move the variables with x to one side...

5x + 20x = -10 + 60

25x = 50

;Therefore...the value of x at intersection point = 2

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Use the rule provided to generate the first five terms of the sequence. The rule<br> is 4n + 5.

lesya692 [45]

Answer:

9, 13, 17, 21,25

Step-by-step explanation:

n=1, 4×1+5=9

n=2, 4×2 +5=13

n=5, 4×5 + 5= 25

4 0

2 years ago

What’s the answer please help

noname [10]

Answer:

$\boxed{\text{A. }\math{\left \{ x \, | \, x \in \mathbb{R}, x < -2 \right \}}}}$

Step-by-step explanation:

The open circle means that the point is not included in the solution set, and the arrow pointing left means that all numbers less than -2 are members.

In set-builder notation, each term has a special meaning. The braces enclose the members of the set.

Here's how you translate the notation,

$\begin{array}{rcl}\\\left \{ & = & \text{The set of}\\x & = & \text{all x values}\\| & = &\text{such that}\\x & = & x\\\in & = &\text{is a member of}\\\mathbb{R}, & = &\text{all real numbers, and}\\x < -2 & = & \text{x is less than -2}\\\end{array}\\\text{The answer is }\boxed{\textbf{A. }\mathbf{\left \{ x \, | \, x \in \mathbb{R}, x < -2 \right \} }}}$