The bearing and distance is from the starting position is 111° and 225.7 miles respectively.
<h3>What is the distance and bearing from the starting position?</h3>
The distance from A to B = 1.4 * 110 = 154 miles
The distance from B to C = 1.5 * 110 = 165 miles
The distance from A to C = x
Using Pythagoras theorem:
x = √(165² + 154²)
x = 225.7 miles
The bearing will be 64° + α
α = tan⁻¹(165/154) = 47°
Bearing from starting position = 64 + 47 = 111°
In conclusion, the bearing and distance is determined using Pythagoras theorem.
<em>Note that the complete question is:</em>
<em>From A to B a private plane flies 1.4 hours at 110 mph on a bearing of 64o. It turns at point B and continues another 1.5 hours at the same speed, but on a bearing of 154o to point C.</em>
<em>At the end of this time, how far is the plane from its starting point?</em>
<em>On what bearing(from due North) is the from its original location?</em>
Learn more about bearing and distance at: brainly.com/question/24142612
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