Ask question

Ask question

All categories

2 years ago

5

Two cars started from the same point. one traveled north at 45 mi/h and the other traveled south at 65 mi/h. how far apart were

the cars after 3 hours?

1 answer:

Igoryamba2 years ago

4 0

They were 30mi away from each other

You might be interested in

A recipe used 2/3 cup of sugar for every 2 teaspoons of butter. How much sugar was used per teaspoon of butter

myrzilka [38]

Answer:

2/3cups 2 teaspoons

(2/3 )cups/2teaspoons =1/3 cups per teaspoon

Answer= 1/3 cups per teaspoon

8 0

2 years ago

Read 2 more answers

What is the order of 4 x 10^-7, 7 x 10^-9, 1 x 10^4, 2 x 10^4

butalik [34]

4 x 10^-7 (7 x 10^-9) (1 x 10^4) (2 x 10^4)

8 0

2 years ago

Read 2 more answers

Sam has $3.30 in quarters and dimes, and the total number of coins is 18. How many quarters and how many dimes?

zhuklara [117]

Answer:

Quarters: 10

Dimes: 8

Step-by-step explanation:

Constraints

value: 0.25q + 0.10d = 3.30

count: q + d = 18

q = 18 - d

0.25(18-d) + 0.10d = 3.30

4.50-0.25d+0.10d = 3.30

4.50-0.15d = 3.30

-0.15d = -1.20

d = 8

q + d = 18

q + 8 = 18

q = 10

Check:

0.25(10) + 0.10(8) = 3.30

2.5+ 0.80 = 3.30

3.30 = 3.30

4 0

2 years ago

A student is given that point P(a, b) lies on the terminal ray of angle Theta, which is between StartFraction 3 pi Over 2 EndFra

Harman [31]

Answer:

<em>A.</em>

<em>The student made an error in step 3 because a is positive in Quadrant IV; therefore, </em>

<em /> $cos\theta = \frac{a\sqrt{a^2 + b^2}}{a^2 + b^2}$

Step-by-step explanation:

Given

$P\ (a,b)$

$r = \± \sqrt{(a)^2 + (b)^2}$

$cos\theta = \frac{-a}{\sqrt{a^2 + b^2}} = -\frac{\sqrt{a^2 + b^2}}{a^2 + b^2}$

Required

Where and which error did the student make

Given that the angle is in the 4th quadrant;

The value of r is positive, a is positive but b is negative;

Hence;

$r = \sqrt{(a)^2 + (b)^2}$

Since a belongs to the x axis and b belongs to the y axis;

$cos\theta$ is calculated as thus

$cos\theta = \frac{a}{r}$

Substitute $r = \sqrt{(a)^2 + (b)^2}$

$cos\theta = \frac{a}{\sqrt{(a)^2 + (b)^2}}$

$cos\theta = \frac{a}{\sqrt{a^2 + b^2}}$

Rationalize the denominator

$cos\theta = \frac{a}{\sqrt{a^2 + b^2}} * \frac{\sqrt{a^2 + b^2}}{\sqrt{a^2 + b^2}}$

$cos\theta = \frac{a\sqrt{a^2 + b^2}}{a^2 + b^2}$

So, from the list of given options;

<em>The student's mistake is that a is positive in quadrant iv and his error is in step 3</em>

3 0

2 years ago

How many times does 8 go into 144

LuckyWell [14K]

8 goes into 144 18 times

6 0

2 years ago

Read 2 more answers