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Blizzard [7]
2 years ago
6

The area of a rectangular painting is 1/6 square yard. The width is 2/3 yard. What is the length of the painting use the formula

a= lxw
Mathematics
1 answer:
STatiana [176]2 years ago
4 0

The length of the painting is 1/4.

According to the statement

we have to find the length of the rectangular painting with the help of the given information.

So, For this purpose, we know that the

The given information is:

The area of a rectangular painting is 1/6 square yard. The width is 2/3 yard.

And we have to use the formula

Area = Length * Breadth

So, Substitute the values in it then solve

So,

Area = Length * Breadth

1/6= Length * 2/3

1/6 = 2L/3

1 = 12L/3

1 = 4L

L = 1/4.

The value of the length is 1/4.

So, The length of the painting is 1/4.

Learn more about area of a rectangle here

brainly.com/question/2607596

#SPJ9

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Haley substituted the values of a, b, and c into the quadratic formula below.
Marysya12 [62]
The quadratic formula is x equals negative b plus or minus the square root of b squared minus four times a times c, all over 2a. 
Looking at the equation, we can find the values for a, b, and c
a=7
b= -10
c= -2

So then putting that back into standard form, which is ax^2+bx+c, we know Haley's function in standard form is 7x^2-10x-2
7 0
3 years ago
Read 2 more answers
The length of a rectangle is 6 inches more than its width. Its area is 91 square inches. The length is .
Vika [28.1K]

Answer:

13 in

Step-by-step explanation:

let w be width then length is w + 6

the area (A) of a rectangle is calculated as

A = length × width , then

A = w(w + 6) = 91 , that is

w² + 6w = 91 ( subtract 91 from both sides )

w² + 6w - 91 = 0 ← in standard quadratic form

(w + 13)(w - 7) = 0 ← in factored form

equate each factor to zero and solve for w

w + 13 = 0 ⇒ w = - 13

w - 7 = 0 ⇒ w = 7

however, w > 0 then w = 7

and length = w + 6 = 7 + 6 = 13 in

8 0
2 years ago
You are working for a company that creates tubes that measure 10 cm long and have a diameter of 6 cm. The tubes need to be cut j
Nataly_w [17]

Answer:

A= 2\pi (3cm)^2 +1 2\pi (3cm)(10 cm)= 18 \pi + 60\pi = 78 \pi cm^2

And replacing the value of \pi =3.14 we got:

A = 78*3.14 cm^2= 244.92 cm^2

Step-by-step explanation:

For this case we have the long who represent the height 10 cm and the diameter is 6cm. So then the radius is given by:

r = \frac{D}{2}= \frac{6cm}{2}= 3cm

And the surface area for a cylinder is given by this formula:

A= 2\pi r^2 +2 \pi rh

And replacing the info given we got:

A= 2\pi (3cm)^2 +1 2\pi (3cm)(10 cm)= 18 \pi + 60\pi = 78 \pi cm^2

And replacing the value of \pi =3.14 we got:

A = 78*3.14 cm^2= 244.92 cm^2

4 0
3 years ago
Can you please help me out
Taya2010 [7]

The bag contains,

Red (R) marbles is 9, Green (G) marbles is 7 and Blue (B) marbles is 4,

Total marbles (possible outcome) is,

\text{Total marbles = (R) + (G) +(B) = 9 + 7 + 4 = 20 marbles}

Let P(R) represent the probablity of picking a red marble,

P(G) represent the probability of picking a green marble and,

P(B) represent the probability of picking a blue marble.

Probability , P, is,

\text{Prob, P =}\frac{required\text{ outcome}}{possible\text{ outcome}}\begin{gathered} P(R)=\frac{9}{20} \\ P(G)=\frac{7}{20} \\ P(B)=\frac{4}{20} \end{gathered}

Probablity of drawing a Red marble (R) and then a blue marble (B) without being replaced,

That means once a marble is drawn, the total marbles (possible outcome) reduces as well,

\begin{gathered} \text{Prob of a red marble P(R) =}\frac{9}{20} \\ \text{Prob of }a\text{ blue marble =}\frac{4}{19} \\ \text{After a marble is selected without replacement, marbles left is 19} \\ \text{Prob of red marble + prob of blue marble = P(R) + P(B) = }\frac{9}{20}+\frac{4}{19}=\frac{251}{380} \\ \text{Hence, the probability is }\frac{251}{380} \end{gathered}

Hence, the best option is G.

5 0
1 year ago
$14,700 list price. 20% trade discount what is paid
Harman [31]
$2,940, because it’s 20% of $14,700
6 0
3 years ago
Read 2 more answers
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