<span>The answer is C.glycolysis ® Krebs cycle ® electron transport chain. There are 3 stages of cellular respiration: 1. glycolysis when glucose is broken down to pyruvate in the cytoplasm; 2. Krebs cycle when Acetyl CoA and oxaloacetate form a 6 C-atoms compound; 3. Electron transport chain when hydrogen molecules removed through previous stages are pumped to the chain and energy is produced.</span>
Answer:
Option 1, No. The highest frequency of heterozygotes under Hardy-Weinberg equilibrium is 0.5
Explanation:
As per Hardy Weinberg’s equilibrium principle, the maximum frequency of heterozytotic individuals occur only when half of the population is dominant and recessive homozygous.
In other way when the sum of frequency of dominant and recessive species is equal to 0.5, only then the frequency of heterozygotes is maximum which in any case would not be higher than 0.5.
Hence, option 1 is correct
Producers:
Hippos,elephants,cattle,antelope,horses
Primary consumers:
Seaweed,phytoplankton,algae,plants,Cyanobacteria
Predators:
Wolf,puma,lion,cheetah,lepard
Answer:
64
Explanation:
Since the population is in Hardy-Weinberg equilibrium and the equilibrium is defined by the equation
p² + 2pq + q²
where the frequency of the homozygous dominant allele F ( feathers on the leg ) = p²,
F of homozygous ( featherless legs) = q²
F of heterogyous ( carrier of featherless allele) = 2pq
F (q²) = 128/200 = 0.64
q = √0.64 = 0.8
and p + q = 1
p = 1 - 0.8 = 0.2
2pq = 2 × 0.2 × 0.8 = 0.32
number of chickens that are heterozgous for the feathered leg allele = 0.32 × 200 = 64
