Answer:
At a certain pizza parlor,36 % of the customers order a pizza containing onions,35 % of the customers order a pizza containing sausage, and 66% order a pizza containing onions or sausage (or both). Find the probability that a customer chosen at random will order a pizza containing both onions and sausage.
Step-by-step explanation:
Hello!
You have the following possible pizza orders:
Onion ⇒ P(on)= 0.36
Sausage ⇒ P(sa)= 0.35
Onions and Sausages ⇒ P(on∪sa)= 0.66
The events "onion" and "sausage" are not mutually exclusive, since you can order a pizza with both toppings.
If two events are not mutually exclusive, you know that:
P(A∪B)= P(A)+P(B)-P(A∩B)
Using the given information you can use that property to calculate the probability of a customer ordering a pizza with onions and sausage:
P(on∪sa)= P(on)+P(sa)-P(on∩sa)
P(on∪sa)+P(on∩sa)= P(on)+P(sa)
P(on∩sa)= P(on)+P(sa)-P(on∪sa)
P(on∩sa)= 0.36+0.35-0.66= 0.05
I hope it helps!
$7.50(2)=$15.00 (She takes the taxi twice, and its $7.50 each time she takes it)
$0.45(16)+$0.45(8)=$10.80 (Each mile is $0.45, she goes 16 miles on the way to work, and only 8 miles on the way home. Since she walks half way and takes the taxi the other half. Half of 16 is 8)
$15.00+$10.80=$25.80
Alexis pays $25.00 per day for her taxi rides.
Answer:
Step-by-step explanation:
I think you are just asking for the decimal answers.
3/20 = 0.15
9/50 = 0.18
38/200 = 0.19
Answer: The car travels 97.5 miles in 1.5 hour.
Step-by-step explanation:
Given: A car is traveling down a highway at a constant speed, described by the equation , described by the equation 
, where represents the distance, in miles, that the car travels at this speed in<em> t</em> hours.
To find : Number of miles car travel in 1.5 hour.
Simply put t= 1.5 in the given expression , we get
65(1.5)= 97.5
That means , the car travels 97.5 miles in 1.5 hour.
Your answer is B because it’s 6 times 3 times 4 and you add cubic because it’s volume.
