This is the concept of algebra: The answers to the questions will be as follows:
1. What is AD/AM in the simplest form:
AD/AB is the ratio of AD to AB. This will calculated as follows:
AD=9 units
AB=3 units
thus:
9/3=3
Hence, we conclude that the answer is D. 3
2] What is slope of BE/ slope of AE in simplest form:
slope=(Δy-axis)/(Δx-axis)
slope of AE
=(5-0)/(4-0)
=5/4
slope BE
slope=(5-0)/(4-3)=5/1=5
therefore the ratio of the two slope will be:
BE/AE
=5/(5/4)
=4
The answer is A.4
3. What is the value of x in the proportion (x-1)/5=(4x+2)/35?
To get the value of x we solve the above proportion:
(x-1)/5=(4x+2)/35
35(x-1)=5(4x+2)
35x-35=20x+10
putting like terms together we get:
35x-20x=10+35
15x=45
dividing both sides by 15
x=45/15
x=3
Hence the answer is B.3
4. What is the value of x in the proportion:
(x+1)/(x+3)=15/21
to get the value of x we solve the above:
first we begin by cross multiplying the proportion, this will give us:
21(x+1)=15(x+3)
21x+21=15x+45
putting like terms together we get:
21x-15x=45-21
6x=24
dividing both sides by 6 we get
x=4
∴ x=4
5. The lengths of the sides of a triangle are in extended ratio 3:10:12. The perimeter is 400 cm. What is the length of the longest side in cm.
solution:
Here we introduce the variable x such that the perimeter is:
3x+10x+12x=400
25x=400
x=400/25
x=16
The longest side will be:
12×16=192 cm
Answer:
3.5
Step-by-step explanation:
Answer:
$720
Step-by-step explanation:
$20000 - 100%
$x. - 2.5%
x=(20000*2.5)/100=500
20000+500=$20500 in one year (Mark)
20000 - 100
x. - 6.1
x= (20000*6.1)/100 = 1220
20000+1220= $21220 (Walter)
21220-20500= $720 more (Walter will have after 1 year)
You can also approach it this way:
28 flowers times n = 3444
so n = 123
11 x 123 = roses, 17 x 123 = tulips.
Those 2 products should add up to 3444. They do. :-)
gotchaaaaaa
ahhh
thanxxx
The small box is 384inches squared for the volume and the larger box is 2,700 inches squared so if you place the smaller box inside the larger box the room left inside the larger box would be 2,316 inches squared
