It’s a little complicated but here’s how it works:
Imagine a table with the intervals
0:4 , 4:6 , 6:7 , 7:10 , 10:13 (10 year intervals)
Then we have different rows
Class width: 4 , 2 , 1 , 3 , 3
Freq density: 0.2 , 0.5 , 1.2 , 0.7 , 0.3
So now calculate frequency where freq = class width * density
Freq: 0.8 , 1 , 3.6 , 2.1 , 0.9
So to find median find cumulative frequency
(Add all freq)
Cfreq = 8.4 now divide by 2 = 4.2
So find the interval where 4.2 lies.
0.8 + 1 = 1.8 + 3.6 = 5.6
So 4.2 (median) will lie in that interval 60-70 years.
Answer:
65%
Step-by-step explanation:
Since percentages are out of 100, you can write 13/20 as (13*5)/(20*5) = 65/100, which translates to 65%
Answer:
answer is 347.6
Step-by-step explanation:
21/7300= 347.6
Given:
Christopher scores 2 goals in a soccer game.
His goal total can vary from the average by 1 goal.
To find:
The absolute value equation can be used to calculate Christopher's maximum and minimum goals per game.
Solution:
Let Christopher scores x goals in a soccer game.
Then difference between actual goals and average goals is x-2.
His goal total can vary from the average by 1 goal.
Maximum number of goals = 2+1 = 3
Minimum number of goals = 2-1 = 1
It means, the difference between actual goals and average goals is either -1 and 1.
...(1)
...(2)
Using (1) and (2),we get

Therefore, the correct option is C.