The solution of
are 1 + 2i and 1 – 2i
<u>Solution:</u>
Given, equation is 
We have to find the roots of the given quadratic equation
Now, let us use the quadratic formula
--- (1)
<em><u>Let us determine the nature of roots:</u></em>
Here in
a = 1 ; b = -2 ; c = 5

Since
, the roots obtained will be complex conjugates.
Now plug in values in eqn 1, we get,

On solving we get,



we know that square root of -1 is "i" which is a complex number

Hence, the roots of the given quadratic equation are 1 + 2i and 1 – 2i
Answer:
No.
Step-by-step explanation:
The numbers aren't going up at a constant rate. Say each lap costs 2 dollars. On lap 4, you have paid 8 dollars total. On lap 9, you have paid 18 dollars total. But the 10th lap is free, which means you pay 0 dollars. In order for this pattern to be constant, you would need to pay 20 dollars, but instead you pay 0.
Step-by-step explanation:
x² = 25/784
Since 25 = 5² and 784 = 28²,
x = ±(5²/28²) = ±5/28.
<span>English: What is the name of the instrument used to measure the degrees of an angle?
responder:
transportador</span>